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3 years ago

Choose the abbreviation of the postulate or theorem that supports the conclusion that the triangles are congruent.

Mathematics

2 answers:

laiz [17]3 years ago

8 0

∠C and ∠F are right angles. So, the triangles are right triangles.

AC = DF are the short legs of both triangles.

∠B = ∠E.

In this scenario, the postulate is ASA (Angle-Side-Angle)

The remaining sides that must be noted to prove that the triangles are congruent are the long legs and hypotenuse.

CB = FE can be LL for congruence where t<span>t states that if the legs of one right triangle are congruent to the legs of another right triangle, then the triangles are congruent.</span>

Inessa [10]3 years ago

4 0

Answer: LA

Step-by-step explanation:

Given: In ΔABC and ΔDEF

∠C, ∠F are right angles

⇒ Both triangles are right triangles.

AC = DF ; ∠B = ∠E

By LA theorem, we get

ΔABC ≅ ΔDEF

The LA theorem tells that for any two right triangles, where one acute angle and a leg of one of the triangles are congruent to an angle and a leg of the other triangle, then the two triangles are congruent.

Hence, LA is the abbreviation of the theorem that supports the conclusion that the triangles are congruent.

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9/8+7/40= and does the answer simplify

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Answer:

1 3/10

Step-by-step explanation:

9/8 +7/40

Get a common denominator of 40

9/8 *5/5 + 7/40

45/40 + 7/40

52/40

Rewriting as

40/40 +12/40

1 + 3/10

1 3/10

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3 years ago

Read 2 more answers

On a coordinate plane, a line has points (negative 2, negative 4) and (4, 2). Point P is at (0, 4). Which points lie on the line

NikAS [45]

Answer:

the correct options are:

(–1, 3), (–2, 2) and (–5, –1)

Step-by-step explanation:

Given that a line passes through two points

A(-2, -4) and B(4, 2)

Another point P(0, 4)

To find:

Which points lie on the line that passes through P and is parallel to line AB ?

Solution:

First of all, let us the find the equation of the line which is parallel to AB and passes through point P.

Parallel lines have the same slope.

Slope of a line is given as:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m=\dfrac{2-(-4)}{4-(-2)} = 1$

Now, using slope intercept form ( $y = mx+c$ ) of a line, we can write the equation of line parallel to AB:

$y =(1)x+c \Rightarrow y = x+c$

Now, putting the point P(0,4) to find c:

$4 = 0 +c \Rightarrow c = 4$

So, the equation is $\bold{y=x+4}$

So, the coordinates given in the options which have value of y coordinate equal to 4 greater than x coordinate will be true.

So, the correct options are:

(–1, 3), (–2, 2) and (–5, –1)

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3 years ago

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Step-by-step explanation:

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3 years ago

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Rashid [163]

Answer:

Step-by-step explanation:

For b, the constant term is 3, not -3. B is incorrect.

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3 years ago

Bayes' rule can be used to identify and filter spam emails and text messages. This question refers to a large collection of real

Blababa [14]

Answer:

0.134 = 13.4% probability that a message is spam, given that it contains the word "text" (or "txt")

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Contains the word "text", or "txt".

Event B: Spam message.

The word "text" (or "txt") is contained in of all messages, and in of all spam messages.

This means that $P(A) = 1$

747 of the 5574 total messages () are identified as spam. The word "text" (or "txt") is contained in all of them. So

$P(A \cap B) = \frac{747}{5574} = 0.134$

Then

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.134}{1} = 0.134$

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