Discussion
The discriminate is b^2 - 4*a*c
The general equation for a quadratic is ax^2 + bx + c
In this equation's case
a = 1
b= -5
c = - 3
Solve
(-5)^2 - 4*(1)*(-3)
25 - (-12)
25 + 12
37
Note
Since the discriminate is > 0, the roots are real and different. The roots do exist and there are 2 of them.
The solution has to be a value of x. Since you already have x, you just have to plug in the value and see what fits. In this case thats the third from the top:
5^2 - 10*5 + 25 = 0
25 - 50 + 25 = 0
0 = 0
Hope it helps!
Answer:
5.4217 • 10¹
Step-by-step explanation:
4.5 • 10⁻² ÷ 8.3 • 10⁻⁴
450 ÷ 8.3
54.21686...
54.217
5.4217 • 10¹
I hope this helps
If the sample is random, it is not valid.
Answer:
Solution set {x|x<8}
Step-by-step explanation:
0.35x - 4.8<5.2- 0.9x
0.35x+0.9x<5.2+4.8
1.25x<10
x<10/1.25
x<8
Solution set {x|x<8}
