All categories

3 years ago

Cscx/secx = cotx Verify with steps please :)

1 answer:

6 0

Csc(x) = 1/sin(x)
sec(x) = 1/cos(x)
cot(x) = [1/sin(x)] / [1/cos(x)]
cot(x) = 1/sin(x) * cos(x)/1
cot(x) = cos(x) / sin(x)
cot(x) = cot(x)

You might be interested in

If a bag contains 12 apples , 4 bananas , and 8 oranges , what part to whole ratio bananas to all fruit

marysya [2.9K]

Answer:

4 : 24 or 1 : 6

Step-by-step explanation:

There are 4 bananas and 24 fruits so we just make that a ratio of 4 : 24.

We can then simplify that ratio to 1 : 6.

7 0

3 years ago

Read 2 more answers

Select the items for which the discount is greater than 15%.circle all that apply. Plz show me work

8_murik_8 [283]

Ex: (A) 19.95÷29.95 and you will get your answers

6 0

3 years ago

Read 2 more answers

Please does anyone know how to do this x

Andre45 [30]

Step-by-step explanation:

Weight before diet: 208 pounds

After diet: 192 pounds

Difference in weight: 16 pounds

(16÷208)*100= 7.7%

4 0

3 years ago

14.31782106 rounded to the nearest foot

Leviafan [203]

I believe it is 14 ..

3 0

3 years ago

The admissions office of a private university released the following admission data for the preceding academic year: From a pool

lina2011 [118]

Answer: Our required probability is 0.1695.

Step-by-step explanation:

Since we have given that

Number of male applicants = 4200

Number of female applicants = 3800

So, total number of applicants = 4200+3800 = 8000

Probability of male entered and subsequently enrolled is given by

$0.4\times 0.4=0.16$

Probability of female entered and subsequently enrolled is given by

$0.4\times 0.45\\\\=0.18$

Number of male entered and subsequently enrolled is given by

$0.16\times 4200\\\\=672$

Number of female entered and subsequently enrolled is given by

$0.18\times 3800\\\\=684$

So, Probability that a student who applied for admission will be accepted by the university and subsequently will enroll is given by

$\dfrac{672+684}{8000}\\\\=\dfrac{1356}{8000}\\\\=0.1695$

Hence, our required probability is 0.1695.

3 0

3 years ago