Step-by-step explanation:
<h3>To find the right matrix, you have to look which matrix among the options has doubled each item.</h3>
For example, if you have:
![\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D)
Then, your answer would be:
![\left[\begin{array}{ccc}2&4&6\\8&10&12\\14&16&18\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%264%266%5C%5C8%2610%2612%5C%5C14%2616%2618%5Cend%7Barray%7D%5Cright%5D)
Because each term is the double of the original matrix.
<h3>Remember that, this operation is between a scalar and a matrix. That operation is done according to this property:</h3>
![aM=a\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] = \left[\begin{array}{ccc}1a&2a&3a\\4a&5a&6a\\7a&8a&9a\end{array}\right]](https://tex.z-dn.net/?f=aM%3Da%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1a%262a%263a%5C%5C4a%265a%266a%5C%5C7a%268a%269a%5Cend%7Barray%7D%5Cright%5D)
<em>In fewer words, the scalar will multiply each element of the matrix.</em>