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svlad2 [7]
4 years ago
15

The vertices of a triangle are A(5,-4), B(7,0),and C(1,-2). If the triangle is a right triangle, which vertex is the right angle

?
Mathematics
1 answer:
Svet_ta [14]4 years ago
5 0
When you plot the points to the graph, the right angle is point A.
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6 bars is .283 each and 4 bars is .2875 SO... 6 bars is the better buy.

Step-by-step explanation:


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Use the T-table below to determine 3 solutions to this equation: y=-4-5<br> x<br> 0<br> 1<br> -2
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4 0
3 years ago
How do I fine x to the nearest tenth ??
Ipatiy [6.2K]

Answer:

x = 13.6

Step-by-step explanation:

Here, we want to find the value of x

to find the value of x. we are going to use the sine rule

It states that the ratio of the sine of an angle to the measure of the side facing the angle is fixed for a triangle

In this case;

11/ sin 27 = x/ sin 34

x = 11 sin 34/sin 27

x = 13.6

4 0
3 years ago
Sara invests $1,200 each year in an IRA ( 12 years in an account that earned 5%
Sati [7]
A)

\bf \qquad \qquad \textit{Future Value of an ordinary annuity}&#10;\\\\&#10;A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]&#10;\\\\

\bf \begin{cases}&#10;A=&#10;\begin{array}{llll}&#10;\textit{original amount}\\&#10;\textit{already compounded}&#10;\end{array}&#10;\begin{array}{llll}&#10;&#10;\end{array}\\&#10;pymnt=\textit{periodic deposits}\to &1200\\&#10;r=rate\to 5\%\to \frac{5}{100}\to &0.05\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{each year, once}&#10;\end{array}\to &1\\&#10;&#10;t=years\to &12&#10;\end{cases}

B)

let's say after 12years, she ended up with a value of say "P"
so.. now she's just sitting on P, making no more deposits to it
just taking whatever the compound 5% interest will give, thus

\bf \qquad \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\qquad &#10;\begin{cases}&#10;A=\textit{compounded amount}\\&#10;P=\textit{original amount deposited}\to &\boxed{P}\\&#10;r=rate\to 5\%\to \frac{5}{100}\to &0.05\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{again, is only once}&#10;\end{array}\to &1\\&#10;&#10;t=years\to &11&#10;\end{cases}


C)

from A) she made 1,200 every year, for 12 years that's 1200*12, that's how much she put out of pocket, if you got an amount P from A), then the interest is just the difference, or P - (1200*12)

from B), she started with an original amount of P, and ended up with a compounded amount of A after 11years, so the interest is just also the difference, or A - P

add those two folks together, and that's the total interest she got for the 23  years



4 0
4 years ago
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