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d1i1m1o1n [39]
3 years ago
5

How do you show the limit does not exist limx→4x−4x2−8x+16lim_(x->4)(x-4)/(x^2-8x+16) ?

Mathematics
1 answer:
fredd [130]3 years ago
5 0
\lim\limits_{x\to4}\frac{x-4}{x^2-8x+16}=\lim\limits_{x\to4}\frac{x-4}{(x-4)^2}=\lim\limits_{x\to4}\frac{1}{x-4}\\\\\lim\limits_{x\to4^-}\frac{1}{x-4}=\frac{1}{0^-}=-\infty\\\\\lim\limits_{x\to4^+}\frac{1}{x-4}=\frac{1}{0^+}=\infty
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If 2(x + 3) = x + 10, then x equals what
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Answer:

x=4

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. You need to apply the Distributive property on the left member of the equation:

2(x + 3) = x + 10\\ 2x+6=x+10

2. Now, you must solve for x, as following:

2x-x=10-6\\ x=4


8 0
3 years ago
The lengths of the sides of a triangle are 3, 3, and the square root 3. Can the triangle be a right triangle?
Readme [11.4K]
First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
 
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If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
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This is larger than 3, this cannot be a right triangle.

The answer is b) no.





8 0
4 years ago
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shtirl [24]

Answer:

Step-by-step explanation:

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3 0
3 years ago
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astraxan [27]

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Depth of titanic = 3,797 m (1 km / 1000 m)

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4 years ago
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guajiro [1.7K]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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