How do you show the limit does not exist limx→4x−4x2−8x+16lim_(x->4)(x-4)/(x^2-8x+16) ?
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Functions, equations and tables can be represented using graphs
- The x-intercepts are: 0, 0.35 and 1.53
- The local maximum is at point (0.17, 0.08), and the local minimum is at point (1.13, -1.07)
The expression is given as:
Rewrite the expression as a function
See attachment for the graph of the function.
<h3>The x-intercepts</h3>This is the point where the graph cross the x-axis.
From the attached graph, the x-intercepts are: 0, 0.35 and 1.53
<h3>The local maximum</h3>From the attached graph, the local maximum is at point (0.17, 0.08)
<h3>The local minimum</h3>From the attached graph, the local minimum is at point (1.13, -1.07)
<h3>Intervals</h3>- The graph increases at interval (-1.30, 0) and (1,13, infinity)
- The graph decreases at interval (- infinity, 1.30) and (0.35, 1.13)
Read more about graphs and functions at: