Is .325 rational or irrational

Complete the paragraph below. The standard deviation is used in conjunction with the ______ to numerically describe distributio

Bumek [7]

Answer:

The standard deviation is used in conjunction with the mean to numerically describe distributions that are bell shaped. The mean measures the center of the distribution, while the standard deviation measures the spread of the distribution.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

The mean is the average value of the measures while the standard deviation measures how spread the measures are from the mean. So

The standard deviation is used in conjunction with the mean to numerically describe distributions that are bell shaped. The mean measures the center of the distribution, while the standard deviation measures the spread of the distribution.

4 0

3 years ago

If a roll of painter's tape contains 14 feet of tape, what is the maximum number of 1.75-foot pieces that can be cut from the ro

Dafna11 [192]

Answer is c 8
8*1.75=14

3 0

2 years ago

Two acute triangles are similar. Which of the following must the similar triangle have?

abruzzese [7]

B is the only one that makes sense if you break them each down. An Acute doesnt have every Pair of angles congruent, the don't have to have proportional side lengths, and it can't have a right angle or it would be a right triangle.

7 0

3 years ago

Read 2 more answers

Shea is making a lot of plates of cookies for his friends. He makes a total of 18,698 cookies and spilts it into 297 equal plate

slavikrds [6]

Answer:

Shea's coworkers received .89 of a cookie each.

Step-by-step explanation:

18,698/297 = 62.9 rounded to 63

63/71 = .887 rounded to .89

.89 cookies

8 0

3 years ago

Compute a · (b ✕ c), where a = i − 3j + k, b = 4i + j + k and c = 9i − j + 3k.

grandymaker [24]

$\mathbf a=\mathbf i-3\,\mathbf j+\mathbf k$
$\mathbf b=4\,\mathbf i+\mathbf j+\mathbf k$
$\mathbf c=9\,\mathbf i-\mathbf j+3\,\mathbf k$

$\mathbf b\times\mathbf c=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\4&1&1\\9&-1&3\end{vmatrix}=4\,\mathbf i-3\,\mathbf j-13\,\mathbf k$

$\mathbf a\cdot(\mathbf b\times\mathbf c)=(\mathbf i-3\,\mathbf j+\mathbf k)\cdot(2\,\mathbf i-3\,\mathbf j-13\,\mathbf k)=4+(-3)^2-13=0$

6 0

3 years ago