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vagabundo [1.1K]
2 years ago
9

There are several characteristics of a parallelogram that can prove a quadrilateral is a parallelogram. Which characteristic wou

ld prove a quadrilateral is a parallelogram?
1.Opposite angles are supplementary
2.Adjacent angles are complementary
3.Adjacent angles are supplementary
4.Opposite angles are equal
Mathematics
2 answers:
NeX [460]2 years ago
7 0

Answer: its 4

Step-by-step explanation:

kirill [66]2 years ago
4 0
The answer would be b
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Colleen recorded the type of trees in the woods near her house.She counted 20 trees and 50 maple trees.What is the experimental
natka813 [3]

Answer: The required probability is \dfrac{8}{125}

Step-by-step explanation:

Since we have given that

Number of spruce tree = 20

Number of maple tree = 50

Total trees = 70

We need to find the experimental probability that the next tree Colleen to get a spruce tree.

So, the probability would be :

(\dfrac{20}{50})^3=(\dfrac{2}{5})^3=\dfrac{8}{125}

Hence, the required probability is \dfrac{8}{125}

5 0
3 years ago
In a study of 775 randomly selected medical malpractice​lawsuits, it was found that 502 of them were dropped or dismissed. Use a
bulgar [2K]

By using a 0.05 significance level, we can conclude that there is sufficient evidence that most medical malpractice lawsuits are dropped or dismissed.

<h3>How to test the claim for the medical malpractice lawsuits?</h3>

Since we have to compare whether the sample proportion is greater than or lesser than the population proportion, a one-tailed test would be used. Also, we would calculate the sample proportion of medical malpractice lawsuits that are dropped or dismissed as follows:

Sample proportion, p = x/n

Sample proportion, p = 502/775

Sample proportion, p = 0.6477

Mathematically, the null and alternative hypothesis is given by:

H₀: p = 0.5

H₁: p > 0.5

For the test statistic can be calculated by using this mathematical expression:

z=\frac{\hat{p}\;-\;p_o}{\sqrt{\frac{p_o(1-p_o)}{n }}  }

Where:

  • \hat{p} represents the sample mean.
  • p_o represents the mean.
  • n represents the number of subjects.

Substituting the given parameters into the formula, we have;

z = (0.6477 - 0.5)/√(0.5(1 - 0.5)/775)

z = 0.1477/√(0.25/775)

z = 0.1477/0.01796

z = 8.224.

For the p-value, we have:

p(z>8.224) = 0.0000

Therefore, the p-value (0.000) is less than the significance level α = 0.05. Based on this, we would reject the null hypothesis.

Read more on malpractice lawsuits here: brainly.com/question/13032617

#SPJ1

5 0
1 year ago
Someone please help me
Lesechka [4]

If these 2 triangles are similar to each other, the corresponding sides have to exist in proportion to one another. The angles would be exactly the same (side length doesn't matter at all!). Going from the bigger triangle to the smaller, KL corresponds to RS; LJ corresponds to SQ; JK corresponds to QR. The ratio of KL:RS is 5:1; the ratio of LJ:SQ is 5:1; the ratiio of JK:QR is 5:1. That means that the sides are all proportionate and the triangles are similar by the SSS postulate. Now that we know that the triangles are similar, we can say that all the corresponding angles are the same by CPCTC but we had to determinte side similiarity first. Your answer is the second choice, SSS

8 0
3 years ago
What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?
astraxan [27]
ANSWER


The value of the expression is
- 1


EXPLANATION

Method 1: Rewrite as product of
{i}^{2}


The expression given to us is,

{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}


We use the fact that
{i}^{2}  =  - 1
to simplify the above expression.



{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  {i}^{0}  \times {i}^{1}  \times {i}^{3}   \times {i}^{2}   \times {i}^{4}


This implies,


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  {i}^{0}  \times {i}^{2}  \times {i}^{2}   \times {i}^{2}   \times {i}^{2} \times {i}^{2}


We substitute to obtain,

{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  1\times  - 1 \times  - 1  \times  - 1\times  - 1 \times  - 1


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  1\times  1 \times   1  \times  - 1 =  - 1


Method 2: Use indices to solve.



{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  = {i}^{0 + 1 + 2 + 3 + 4}



This implies that,


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  = {i}^{10}




{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  (  {{i}^{2}} )^{5}


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  (   - 1 )^{5}   =  - 1


8 0
3 years ago
Read 2 more answers
Solve by completing the square
HACTEHA [7]

Answer: x  =  − 1  ± i√ 23

5 0
2 years ago
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