Answer:
a. v(t)= -6.78
+ 16.33 b. 16.33 m/s
Step-by-step explanation:
The differential equation for the motion is given by mv' = mg - γv. We re-write as mv' + γv = mg ⇒ v' + γv/m = g. ⇒ v' + kv = g. where k = γ/m.Since this is a linear first order differential equation, We find the integrating factor μ(t)=
=
. We now multiply both sides of the equation by the integrating factor.
μv' + μkv = μg ⇒ v' + kv = g ⇒ [v]' = g. Integrating, we have
∫ [v]' = ∫g
v = 
+ c
v(t)= + c
.
From our initial conditions, v(0) = 9.55 m/s, t = 0 , g = 9.8 m/s², γ = 9 kg/s , m = 15 kg. k = y/m. Substituting these values, we have
9.55 = 9.8 × 15/9 + c
= 16.33 + c
c = 9.55 -16.33 = -6.78.
So, v(t)= 16.33 - 6.78. m/s = - 6.78 + 16.33 m/s
b. Velocity of object at time t = 0.5
At t = 0.5, v = - 6.78
+ 16.33 m/s = 16.328 m/s ≅ 16.33 m/s
Answer:
120 000 m^2
Step-by-step explanation:
I ASSUME you're being asked to convert from km^2 to m^2.
For this you need to identify the conversion rate, which is 1 000 000 m^2 / 1 km ^2. Multiply by the thing you're converting from and cancel the units.
(1 000 000 m^2 / 1 km ^2) x 0,12 km^2 = 120 000 m^2 (the km^2 cancels out, leaving you only with your target unit of m^2)
Answer:
Check the explanation
Step-by-step explanation:
kindly check the attached image below to Determine whether the given set S is a subspace of the vector space <u><em>(which is contained within a different vector space. So all the subspace is a kind of vector space in their own way, although it is also defined relative to some of the other larger vector space. The linear subspace is more often than not simply called a subspace whenever the situation serves to differentiate it from other types of subspaces.)</em></u> V.A
9514 1404 393
Answer:
6. step 2; terms are improperly combined; it should be -61n-8=-8
7. no; point (2, 5) is not part of the solution in the left graph
Step-by-step explanation:
6. Step 2 should be ...
-61n -8 = -8 . . . . . because -5n-56n = -61n, not -51n
__
7. The boundary lines of both graphs go through the point (2, 5). In the left graph, the line is dashed, indicating that points on the line are not part of the solution set. The point (2, 5) on the dashed line is not a solution to that inequality.
The solid boundary line indicates that the points on the line are part of the solution set. The point (2, 5) on the solid line is a solution to that inequality.
The point (2, 5) is not a solution to both inequalities.
Answer:WFG=116
Step-by-step explanation:
