Question

A tree that is 10 yards tall and casts a shadow 14 yards long. find the angle of elevation from the tip of the shadow to the top of the tree. Round to the nearest degree
-54 degrees
- 36 degrees
- 46 degrees
- 44 degrees

Answer 1

Answer:

36 degrees

Step-by-step explanation:

Refer the attached figure .

Height of tree i.e. AB = 10 yards

Length of shadow i.e. BC = 14 yards .

We are required to find the angle of elevation from the tip of the shadow to the top of the tree. i.e. ∠ACB

Now, we will use trigonometric ratio.

$tan\theta = \frac{Perpendicular}{Base}$

$tan\theta = \frac{AB}{BC}$

$tan\theta = \frac{10}{14}$

$tan\theta =0.714$

$\theta =tani^{-1}0.714$

$\theta =35.52^{\circ}$

Thus the angle of elevation is 35.52° ≈ 36°

Hence  the angle of elevation from the tip of the shadow o the top of the tree. i.e. ∠ACB  is 36°

Answer 2

The correct answer is 36 degrees.