What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?
1 answer:
First we need to find delta for function ax2+bx+c = 0
DELTA = b2-4ac
DELTA = 25 -( 4*1*5)= 25 - 20 = 5
x1 = (-b-√DELTA)/2a = (-5 - √5)/2
x2 = (-b+√DELTA)/2a (-5+√5)/2
x1 and x2 are zeros of this function
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Answer:
Y = -X - 7
Step-by-step explanation:
y-y1 =m(x-x1)
y-(-2)= -1(x-(-5)
y+2 = -1(x+5)
Solve for y
subtract 2 from both sides
y=-x-5-2
Y = -x-7
Go to this link and they will teach you
https://www.khanacademy.org/math/algebra/two-var-linear-equations/slope/v/slope-of-a-line-2
Answer:
b
Step-by-step explanation:
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Answer:
2
Step-by-step explanation:
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