All categories

3 years ago

9. please please help me out ill mark you brainlist

Mathematics

1 answer:

Ymorist [56]3 years ago

6 0

Answer:

C. The scale factor is less than one.

Step-by-step explanation:

By definition, similar triangles have equal angles and proportional corresponding side lengths. Thus, A, B, and D are all mutually exclusive, leaving C the only possible answer. Upon further inspection, the scale factor is indeed greater than one (each side length is scaled by a factor of two, which is large than one)

You might be interested in

Find the product of z1 and z2, where z1 = 2(cos 70° + i sin 70°) and z2 = 4(cos 200° + i sin 200°)

vazorg [7]

Answer:

-8i

Step-by-step explanation:

To multiply numbers is polar form

z1 = r1 ( cos theta 1 + i sin theta 1)

z2 = r2 ( cos theta 2 + i sin theta 2)

z1*z2 = r1*r2 (cos (theta1+theta2) + i sin (theta1+theta2)

z1 = 2(cos 70° + i sin 70°)

z2 = 4(cos 200+ i sin 200)

z1z2 = 2*4 (cos (70+200) + i sin (70+200)

z1z2 = 8 (cos(270) + i sin (270))

= 8 (0 + i (-1))

=-8i

5 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP FIND THE MEASUREMENT QP 20 POINTS

ahrayia [7]

Answer:

a^2+b^2=c^2

a^2+b^2=8^2

a^2+b^2=64

32+32=64

5.66^2+5.66^2=8^2

Step-by-step explanation:

please mark brainiest

please give 5 stars

thank you

5 0

3 years ago

Use substitution to solve the following system of equations. Show all of your work. Write the solution as an ordered pair.

trapecia [35]

Answer:

$\left \{ {{x=2} \atop {y=2}} \right.$

Step-by-step explanation:

Substitute the second equation into the first one:

$4x+(2x-2)=10\\6x-2=10\\6x=12\\x=2$

Substitute $x=2$ into the second equation:

$y=2\times 2-2\\y=4-2\\y=2$

$\therefore \left \{ {{x=2} \atop {y=2}} \right.$

3 0

2 years ago

The table shows y as a function of x. Suppose a point is added to this table. Which choice gives a point that preserves the func

Hunter-Best [27]

Answer:

A) (-5,7)

Step-by-step explanation:

Functions and Relations

A set of values A can have a relation with another set B as long as at least one element of A has at least one image in B. Functions are special relations where each element of A (the domain of the function) has one and only one image on B (the range of the function).

By looking at the options, we can see that x=9, x=-8, and x=-1 already have defined values in Y, so if we define another value for any of them the relation will stop being a function. The only possible choice to preserve the function is the option

$\boxed{A)\ (-5,7)}$

8 0

3 years ago

I WILL GIVE BRAINLIEST 6TH GRADE MATH

yaroslaw [1]

Answer:

Step-by-step explanation: If you count a the answer will be 48

5 0

3 years ago

Read 2 more answers