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icang [17]
3 years ago
15

What is the point slope form for 2x + 3y = 1,470

Mathematics
1 answer:
Jlenok [28]3 years ago
4 0
Idkdididkdkidirkdidkdkdidkd
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Can someone help me on this plz thankyou!!
kipiarov [429]
G(x) is a translation of f(x) 5 units up
Giving us g(x)=f(x)+5
So k=5
4 0
3 years ago
Convert 2 Liters to gallons. Use the fact that 1 gal.= 3.8L.
iris [78.8K]

we know that

1 gal.= 3.8L

we can also write as

3.8L=1 gal

Firstly, we will find for 1L

so, we can divide both sides by 3.8

\frac{3.8}{3.8} L=\frac{1}{3.8}gal

1 L=\frac{1}{3.8}gal

now, we will multiply both sides by 22

22*1 L=22*\frac{1}{3.8}gal

22L=5.78947 gal

22L=5.8 gal

so, option-b.............Answer

8 0
3 years ago
Pls Help Choose the correct word to complete the statement: If BC intersects circle A only at point B, and mCBA = 90°, then CB i
cricket20 [7]

Line CB touches circle A only at one point (point B), hence CB is a tangent.

<h3>What is a circle?</h3>

A circle is the locus of a point such that its distance from a fixed point (center) is always constant.

When a line intersects a circle in exactly one point the line is said to be tangent to the circle

Hence since Line CB touches circle A only at one point (point B), hence CB is a tangent.

Find out more on circle at: brainly.com/question/24375372

7 0
2 years ago
mikes deli just sold 328 ham sandwiches this week. around how many ham sandwiches did mike sold every day this week?
Alenkasestr [34]

Answer:

46.9

Step-by-step explanation:

328/7 = 46.9

To double check: 46.9 x 7 = 328

Have an amazing day!!

PLEASE RATE!!

4 0
2 years ago
The speed of a car after accelerating for 8 seconds is inversely proportional to its weight. The car weighs 1600 kg and accelera
STatiana [176]

Answer:

With 800 extra kg load: speed = 66.667 km/h

With 2400 extra kg load: speed = 40 km/h

Step-by-step explanation:

Let's call the weight of the car W = 1600 kg, and its speed after accelerating for 8 seconds with this weight S = 100 km/h

If we load the car with 800 extra kg, the total weight will be:

W2 = W + 800 = 2400 kg

The relation between the weights is:

W2 / W = 2400 / 1600 = 1.5

If the weight increased 1.5 times, the relation between the speeds will be 1/1.5 (as they are inversely proportional), so:

S2 / S = 1 / 1.5

S2 = S / 1.5 = 66.667 km/h

If we load the car with 2400 extra kg, the total weight will be:

W3 = W + 2400 = 4000 kg

The relation between the weights is:

W3 / W = 4000 / 1600 = 2.5

If the weight increased 2.5 times, the relation between the speeds will be 1/2.5, so:

S3 / S = 1 / 2.5

S3 = S / 2.5 = 40 km/h

3 0
3 years ago
Read 2 more answers
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