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Debora [2.8K]
3 years ago
7

5n = 8n + 30 help me pleaseeeeee

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
6 0

Answer:

n = -10

Step-by-step explanation:

5n = 8n + 30

you move 8n over by subtracting it from both sides

5n -8n = 8n -8n +30

add like terms

-3n = 30

then divid both sides by -3

-3n/-3 = 30/-3

n = -10

fgiga [73]3 years ago
3 0
To find n
1. Subtract 8n from both side to get -3n=30
2. Divide both sides by -3 to get n=-10
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3 years ago
A circle has a circumference of 144π. What is the radius of the circle?
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3 years ago
If g(x)= square root of 3-5x, find the domain of g'(x).
BaLLatris [955]

Answer:

domain: x>3/5

Step-by-step explanation:

First we need to derive our function g(x) to get a new function g'(x)

To do this we will have to apply chain rule because we have an inner and outer functions.

Our G(x) = square root(3-5x)

Chain rule formula states that: d/dx(g(f(x)) = g'(f(x))f'(x)

where d/dx(g(f(x)) = g'(x)

g(x) is the outer function which is x^1/2

f(x) is our inner function which is 3-5x

therefore f'(x)= 1/2x^(-1/2) and f'(x) = -5

g'(f(x)) = -1/2(3-5x)^(-1/2)

Applying chain rule then g'(x) = 1/2 (3-5x)^(-/1/2)*(-5)

But the domain is the values of x where the function g'(x) is not defined

In this case it will be 3-5x > 0, because 3-5x is a denominator and anything divide by zero is infinity/undefined

which gives us x >3/5

5 0
3 years ago
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3 years ago
X^2 + x^2=6^2 what is x​
nikitadnepr [17]

Answer:

x = ±3 sqrt(2)

Step-by-step explanation:

x^2 + x^2=6^2

Combine like terms

2x^2 = 6^2

Divide each side by 2

x^2 = * 6^2/2

Take the square root of each side

sqrt(x^2) =± sqrt(  6^2/2)

Remember that sqrt(a/b) = ±sqrt(a ) /sqrt(b)

x = ±sqrt(6^2)/sqrt(2)

x = ±6 /sqrt(2)

We do not leave square roots in the denominator, so we multiply the top and bottom by sqrt(2)

x = ±6 /sqrt(2) * sqrt(2)/ sqrt(2)

x = ±6 *sqrt(2) /( sqrt(2)*sqrt(2))

x =  ±6 sqrt(2) /(2)

x = ±3 sqrt(2)

5 0
3 years ago
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