Let
x = number of rs 50
y = number of rs 20
z = number of rs 10
Because there are 25 total notes,
x + y + z = 25 (1)
The ratio of rs 50 to rs 20 is 3:5, therefore
x = 0.6y (2)
The total amount is rs 590, therefore
50x + 20y + 10z = 590
or
5x + 2y + z = 59 (3)
Subtract (1) from (3).
4x + y = 34 (4)
Substitute (2) into (4).
4*(0.6y) + y = 34
3.4y = 34
y = 10
From (2), obtain
x = 6
From (1), obtain
z = 25 - 6 - 10 = 9
Answer:
Kaveri has
6 rs 50 notes,
10 rs 20 notes,
9 rs 10 notes.
Answer:
A certain amount I do not know
How much we need for start-up supplies . . . . . $25
AFTER start-up supplies we want to have . . . $70
Total amount we need to get started . . . (25 + 70) = $95
Number of people contributing . . . (me + 4) = 5
<em>Amount each person needs to kick in</em> . . . (95/5) = <em>$19</em>
As your preliminary Accountant, please reserve me one dozen (13) bagels from the first batch you produce !
Given :
The sequence is -5 , -2 , 3 , 10 , 19 .
To Find :
The nth term of the given sequence .
Solution :
Difference between first 2 terms :
-2 - ( -5 ) = 3 1 term
3 - ( -2 ) = 5 2 term
10 - 3 = 7 3 term
19 - 10 = 9 4 term
From the above observation we can say that difference is increasing in odd number .
So, the nth term will be :
for n greater than equal to 0.
Hence, this is the required solution.
Hello,
u(n)=2n+5
u(1)=2*1+5=7
u(2)=2*2+5=9
u(3)=2*3+5=11
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