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olya-2409 [2.1K]

3 years ago

15

A parachutist's rate during a free fall reaches 180 kilometers per hour. What is this rate in meters per second? At this rate, h

ow many meters will the parachutist fall during 5 seconds of free fall? Do not round your answers.

2 answers:

Dmitrij [34]3 years ago

6 0

Answer:

550 meters are covered

Step-by-step explanation:

Elina [12.6K]3 years ago

5 0

Answer:

3000 meters per second

Step-by-step explanation:

!80 kilometers is equal to 1000 meters, so multiply 180 by 1000 and get 180,000 meters. Divide 180,000 by 60, since there are 60 seconds in a single minute, and you get the answer 3000, with the units being meters/second

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If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.

oksian1 [2.3K]

Answer:

$NK = 15$

$JL = 26$

$KL = 19.85$

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

Step-by-step explanation:

Given

$MK = 30$

$NL = 13$

$\angle MKL = 41$

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

$NK = \frac{1}{2} * MK$

$NK = \frac{1}{2} * 30$

$NK = 15$

Solving (b): JL

JL is a diagonal, and it is twice of NL.

$JL = 2 * NL$

$JL = 2 * 13$

$JL = 26$

Solving (c): KL

To solve for KL, we consider triangle KNL where:

$\angle KNL = 90$

and

$KL^2 = NL^2 + NK^2$

$KL^2 = 13^2 + 15^2$

$KL^2 = 394$

$KL = \sqrt{394$

$KL = 19.85$

Solving (d - h):

To do this, we consider triangle JKN

$\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90$ -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

$\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41$

Similarly:

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41$

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49$

So:

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = \angle MLJ + \angle JLK$

$\angle MLK = 49 + 41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

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16⎯⎯⎯⎯√ – (14 + 2) : 2

ollegr [7]

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3 years ago

the weights of three children are in the proportion of 6 :5 :4. If the weight of the lightest child is 24kg, find the weights of

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Answer:

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You roll a fair six sided die twice. The first roll shows a six and the second row shows 3

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Answer:

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Step-by-step explanation:

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2 years ago

Given the function f(x)= 14x^2 + 5x - 1 answer the question if you could change the 14 to any other number, but the rest has to

polet [3.4K]

This is a polynomial of degree 2, and remember that complex roots always come in pairs; therefore, in a second degree polynomial you can only have 0 real roots and 2 complex roots, or 2 real roots and 0 complex roots. There is no way you can have 1 real root and 1 complex root because, as stated before, complex (non-real) roots always come in pairs; so the only way of having 1 real root is dumping the polynomial of degree 2 ( $14 x^{2}$ ) by changing the 14 to 0. That way we'll left with $f(x)=5x-1$ which only has one real root:
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3 years ago

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