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Ad libitum [116K]
2 years ago
11

If s = 1 over 3 unit and A = 18s2, what is the value of A, in square units? ____ square unit(s). (Input whole number only.)

Mathematics
2 answers:
Alexxandr [17]2 years ago
6 0

Answer:  The required value of A is 2 square units.

Step-by-step explanation:  We are given the following values for s and A :

s=\dfrac{1}{3}~\textup{unit}~~~~\textup{and}~~~A=18s^2.

We are to find the value of A in square units.

To find the value of A, we need to substitute the value of s in the expression for A.

Therefore, we get

A=18s^2=18\times\left(\dfrac{1}{3}\right)^2=18\times\dfrac{1}{9}=2~\textup{sq. units}.

Thus, the required value of A is 2 square units.

arsen [322]2 years ago
3 0
S=\frac{1}{3}
A=18s^{2}
A=18*(\frac{1}{3 )^{2} }
A=2
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Find<br>a,b<br>such<br>that 7.2, a, b, 3 are in A.P.​
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Answer:

  • The value of a = 5.8
  • The value of b = 4.4

Step-by-step explanation:

Given

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as

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2b\:=\:a\:+\:3

Putting b = 2a - 7.2

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\mathrm{Add\:}14.4\mathrm{\:to\:both\:sides}

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4a=a+17.4

4a-a=a+17.4-a

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\frac{3a}{3}=\frac{17.4}{3}

a=5.8

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b=2\left(5.8\right)-7.2

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3 years ago
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