Ask question

Ask question

All categories

3 years ago

7

The graph of a line goes up and to the right when

1 answer:

insens350 [35]3 years ago

4 0

It has a positive slope.

You might be interested in

What is the length x of PQ

Bas_tet [7]

Answer:

11.2

Step-by-step explanation:

If the rectangulars are similar then we can use similarity ratio to calculate value of x

CD is similar to RS and AB is similar to QP

4/6.4 = 7/x cross multiply expressions

4x = 44.8 divide both sides by 4

x = 11.2

6 0

2 years ago

What is the GCF of 28a^3 b and 16ab ? <br><br> A)4ab<br> B)4a3b<br> C)28ab<br> D)112a3b2

N76 [4]

28a⁴b: 2 · 2 · 7 · a · a · a · a · b
16ab: 2 · 2 · 2 · 2 · a · b

GCF(28a⁴b, 16ab) = 4ab

The answer is A.

7 0

3 years ago

Determine the measure of ∠FGC. A) 22° B) 70° C) 110° D) 120°

salantis [7]

Answer:

C

Step-by-step explanation:

3 0

2 years ago

Three friends were helping to push a car. If all three are pushing equally hard and the net force is 600N, how hard is each one

slavikrds [6]

Answer:

One person is pushing the car in the net force of 200N

Step-by-step explanation:

600 divided by 3 (600 N in total, and 3 person pushing.)

5 0

2 years ago

If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A

anygoal [31]

Answer:

The value of the given expression is

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

Step by step Explanation:

Given that $tanA=a$

To find the value of $\frac{sin4A-2sin2A}{sin4A+2sin2A}$

Let us find the value of the expression :

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A}$ ( by using the formula $sin2A=2cosAsinA$ here A=2A)

$=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}$

$=\frac{(cos2A-1)}{(cos2A+1)}$

$=\frac{(-(1-cos2A))}{(1+cos2A)}$ (using $sin^2A+cos^2A=1$ here A=2A)

$=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}$ (using $cos2A=cos^2A-sin^2A$ here A=2A)

$=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}$

$=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}$

$=\frac{-2sin^2A}{2cos^2A}$

$=-\frac{sin^2A}{cos^2A}$

$=-tan^2A$ ( using $tanA=\frac{sinA}{cosA}$ here A=2A )

$=-a^2$ (since tanA=a given )

Therefore $\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

6 0

2 years ago