Answer: s=12
Step-by-step explanation:
s(12-3)=108
12s-3s=108
9s=108
Divide both sides by 9
s=12
Answer:
62
Step-by-step explanation:
its 62
The maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus
<h3>Calculating Maximum speed</h3>
From the question, we are to determine how much greater the maximum walking speed of Giraffe is to that of Hippopotamus
From the give information,
The maximum walking speed, S, is given by
S = √gL
Where g = 32ft/sec
and L is the length of the animal's leg
Thus,
For a Giraffe with a leg length of 6 feet
S = √32×6
S = √192
S = 13.856 ft/sec
For a Hippopotamus with a leg length of 3 feet
S = √32×3
S = √96
S = 9.798 ft/sec
Now, we will determine how many times greater 13.856 is than 9.798
13.856/9.798 = 1.41
Hence, the maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus
Learn more on Calculating Speed here: brainly.com/question/15784810
#SPJ1
Answer:
Exact form : 3/10
Decimal form : 0.3
Step-by-step explanation: To subtract fractions, find the LCD (Least Common Denominator) and then combine.
Hope this helps you out! If you need anymore help with math, let me know and I will be more than happy to help you out! ☺
-Karleif Jonsi-
