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Burka [1]
3 years ago
8

A number is randomly selected from ">{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}.

Mathematics
1 answer:
Marysya12 [62]3 years ago
6 0

Answer:

6/20 chance or a 3/10(same thing )

Step-by-step explanation:

there are 20 numbers and only six of the are over 7 making a 6/20 chance or 3/10

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iragen [17]

Answer:

m+n=9

Step-by-step explanation:

Put the equation into the form ka^mb^n by multiplying the coefficients (-1*2*-3), so k= 6, then add the exponents of a together, a^2+a^1= a^3, m=3.

Now you have 6a^3, next we do the exponents of b together, b^3, b^2, b^1= b^6, n=6.

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3 years ago
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Romashka [77]

Answer:

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Determine and prove what shape is formed for the given coordinates for ABCD, and then find the
ella [17]

Answer:

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Step-by-step explanation:

Plot points A (10,-4), B (6,-7), C (3,-3), D (7,0) on the coordinate plane.

Find slopes of the sides:

AB:\ \dfrac{-7-(-4)}{6-10}=\dfrac{3}{4}\\ \\BC:\ \dfrac{-3-(-7)}{3-6}=-\dfrac{4}{3}\\ \\CD:\ \dfrac{0-(-3)}{7-3}=\dfrac{3}{4}\\ \\DA:\ \dfrac{-4-0}{10-7}=-\dfrac{4}{3}

The slopes of opposite sides are the same, so opposite sides are parallel. The slopes of adjacent sides have product of -1, then adjacent sides are perpendicular.

Find the lengths of all sides:

AB=\sqrt{(10-6)^2+(-4-(-7))^2}=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}=5\ units\\ \\BC=\sqrt{(6-3)^2+(-7-(-3))^2}=\sqrt{3^2+4^2}=\sqrt{16+9}=\sqrt{25}=5\ units\\ \\CD=\sqrt{(3-7)^2+(-3-0)^2}=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}=5\ units\\ \\AD=\sqrt{(10-7)^2+(-4-0)^2}=\sqrt{3^2+4^2}=\sqrt{16+9}=\sqrt{25}=5\ units\\ \\

All four sides are of the same length.

Quadrilateral ABCD is a square (all sides of equal length and perpendicular)

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