That would be 5(3w + 13)
The GCF is 5
The equation has one extraneous solution which is n ≈ 2.38450287.
Given that,
The equation;

We have to find,
How many extraneous solutions does the equation?
According to the question,
An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.
To solve the equation cross multiplication process is applied following all the steps given below.

The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y
with 0 and solve for x. The graph of the equation is attached.
n ≈ 2.38450287
Hence, The equation has one extraneous solution which is n ≈ 2.38450287
For more information refer to the link.
brainly.com/question/15070282
Answer:
Only A and C are functions.
Step-by-step explanation:
X-values cannot repeat in the case of functions.
Answer:
0.35865 and 0.35867
Step-by-step explanation:
for this number, the hundreths thousandths place is
0.358659 (bolded)
so, since the 9 rounds up, the estimated number would be 0.35866
the numbers before would be 0.35865 and after, 0.35867