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3 years ago

Could two lines with negative slope be perpendicular? Explain.

1 answer:

3 0

No. For two lines to be perpendicular their slope must be the negative reciprocals of one another, mathematically:

m1*m2=-1

So if the slope of one line is negative, the line perpendicular to this must be positive by definition.

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If tan 0 = 3, find the value of tan 0 + tan(0 + 7) + tan(0 + 27).

Svet_ta [14]

Answer:

1.304

Step-by-step explanation:

I am not sure for the answer

6 0

3 years ago

A classroom globe has a diameter of 12 inches. What is the volume of the globe?

olga_2 [115]

So to find the volume of a sphere you do 4/3 x pi x radius squared

So you would do 4/3 x pi x 6 = 25.13274123

8 0

3 years ago

Read 2 more answers

The sum of the number 27 + 18 also their GCF and another sum

bagirrra123 [75]

I think it’s 45 but I may be wrong

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3 years ago

- Polynomial Functions -For each function, state the vertex; whether the vertex is a maximum or minimum point; the equation of t

vladimir2022 [97]

EXPLANATION

Given the function f(x) = (x-6)^2 + 1

$\mathrm{The\: vertex\: of\: an\: up-down\: facing\: parabola\: of\: the\: form}\: y=ax^2+bx+c\: \mathrm{is}\: x_v=-\frac{b}{2a}$

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

$=x^2-12x+37$ $\mathrm{The\: parabola\: params\: are\colon}$ $a=1,\: b=-12,\: c=37$ $x_v=-\frac{b}{2a}$ $x_v=-\frac{\left(-12\right)}{2\cdot\:1}$ $\mathrm{Simplify}$ $x_v=6$ $y_v=6^2-12\cdot\: 6+37$

Simplify:

$y_v=1$

$\mathrm{Therefore\: the\: parabola\: vertex\: is}$ $\mleft(6,\: 1\mright)$ $\mathrm{If}\: a$ $\mathrm{If}\: a>0,\: \mathrm{then\: the\: vertex\: is\: a\: minimum\: value}$ $a=1$ $\mathrm{Minimum}\mleft(6,\: 1\mright)$ $\mathrm{For\: a\: parabola\: in\: standard\: form}\: y=ax^2+bx+c\: \mathrm{the\: axis\: of\: symmetry\: is\: the\: vertical\: line\: that\: goes\: through\: the\: vertex}\: x=\frac{-b}{2a}$

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

$y=x^2-12x+37$ $\mathrm{Axis\: of\: Symmetry\: for}\: y=ax^2+bx+c\: \mathrm{is}\: x=\frac{-b}{2a}$ $a=1,\: b=-12$ $x=\frac{-\left(-12\right)}{2\cdot\:1}$ $\mathrm{Refine}$

Axis of simmetry : x=6

The quadratic function has the same shape than the parent function y=x^2 because there is NOT a coefficient within x.

3 0

1 year ago

PLEASEEE HELP ME WITH THISSS

zaharov [31]

Answer:

x=14

Step-by-step explanation:

This is asking for the ratio of A to B.

The x-10 is 1.

The 28 is 7.

Find the scale factor by executing 28/7=4.

So, you would want polygon A to be 4 in order to be proportional to polygon B.

Now, you can just guess and check that 14-10=4

Or, you can set up the equation as follows: x-10 = 4

+10 +10

x = 14 is your answer.

4 0

3 years ago