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marshall27 [118]
3 years ago
12

Could two lines with negative slope be perpendicular? Explain.

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0
No.  For two lines to be perpendicular their slope must be the negative reciprocals of one another, mathematically:

m1*m2=-1

So if the slope of one line is negative, the line perpendicular to this must be positive by definition.
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Rewrite the expression with rational exponents as a radical expression.
SpyIntel [72]
I think it’s the last one but I’m not sure. Let me know if you get it right.
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1 year ago
Kaylee drove 75.5 miles in 54 minutes,if she continues to drive at the same rate, how long will it take her to drive 250 miles?
Crazy boy [7]

Answer:

179 minutes

Step-by-step explanation:

  1. Divide both sides by 75.5 to see how many minutes it would take to drive 1 mile. (54 / 75.5) =108/151
  2. She can drive 1 mile in 108/151 minutes
  3. Times by 250. (108/151 * 250) 178.8
  4. 179 to nearest minute
7 0
3 years ago
Do the ratios 2/5 and 6/15 form a proportion?
Ivanshal [37]
Yes because because if you multiply 3 to 2 and 5 you’ll get 6/15
3 0
2 years ago
Read 2 more answers
A random sample of 747 obituaries published recently in Salt Lake City newspapers revealed that 344 (or 46%) of the decedents di
cupoosta [38]

Answer:

The probability value is almost equal to 0. Implying that the proportion of people dying  in that particular interval if deaths occurred randomly throughout the year is unusual.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of decedents who died in the three-month period following their birthdays.

A random sample of 747 obituaries published recently in Salt Lake City newspapers revealed that 344 (or 46%) of the decedents died in the three-month period following their birthdays (123).

The probability (p) of anyone dying in any quarter if people die randomly during the year is simply 0.25.

The random variable <em>X</em> follows a Binomial distribution with parameters n = 747 and p = 0.25.

But the sample selected is too large and the probability of success is small.

So a Normal approximation to binomial can be applied to approximate the distribution of <em>p</em> if the following conditions are satisfied:

  1. np ≥ 10
  2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=747\times 0.25=186.75>10\\n(1-p)=747\times (1-0.46)=560.25>10

Thus, a Normal approximation to binomial can be applied.

So,  p\sim N(\hat p,\ \frac{\hat p(1-\hat p)}{n}).

Compute the probability that 46% or more would die in that particular interval if deaths occurred randomly throughout the year as follows:

P (p\geq 0.46)=P(\frac{p-\hat p}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}>\frac{0.46-0.25}{\sqrt{\frac{0.25(1-0.25)}{747}}})

                   =P(Z>13.25)\\=1-P(Z

 *Use a <em>z</em> table for the probability.

The probability value is almost equal to 0. This probability is very low indicating that the proportion of people dying  in that particular interval if deaths occurred randomly throughout the year is unusual.

3 0
3 years ago
PLZ HELP
docker41 [41]

Answer:

61

Step-by-step explanation:

a_{1}=5\\a_{n}=2a_{n-1}+3\\a_{2}=2*5+3=13\\a_{3}=2*13+3=29\\a_{4}=2*29+3=61

3 0
2 years ago
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