The boxes can weight at most 5 grams less than the desired amount, so they can't be lighter than
grams
Similary, they can't weight more than 5 grams more than the desired amount, so they can't be heavier than
grams
So, the acceptable range is between 208 and 218.
D=6b Since that you want to know the cost of the amount of boxes of strawberries you have bought. The cost is dependent on the number of boxes you have which is why the equation is d=6b. Hope this helps. :)
Answer:
9x
Step-by-step explanation:
Since you are subtracting a negative from a positive you would get 9
<span>(2n^2 + 5n + 3)(4n – 5)
= 8n^3 -10n^2 + 20n^2 - 25n + 12n - 15
= 8n^3 + 10n^2 - 13n - 15
answer is </span><span>A. 8n^3 + 10n^2 – 13n – 15
hope that helps</span>
![4-x^2=x\\ x^2+x-4=0\\ \Delta=1^2-4\cdot1\cdot(-4)=1+16=17\\ x_1=\dfrac{-1-\sqrt{17}}{2}\\ x_2=\dfrac{-1+\sqrt{17}}{2}\\\\ \displaystyle V=\pi\int\limits_0^{\dfrac{-1+\sqrt{17}}{2}}(4-x^2-x)^2\,dx\\ V=\pi\int\limits_0^{\dfrac{-1+\sqrt{17}}{2}}(16-4x^2-4x-4x^2+x^4+x^3-4x+x^3+x^2)\,dx\\ V=\pi\int\limits_0^{\dfrac{-1+\sqrt{17}}{2}}(x^4+2x^3-7x^2-8x+16)\,dx\\ V=\pi \left[\dfrac{x^5}{5}+\dfrac{x^4}{2}-\dfrac{7x^3}{3}-4x^2+16x\right]_0^{\dfrac{-1+\sqrt{17}}{2}}\\ ](https://tex.z-dn.net/?f=4-x%5E2%3Dx%5C%5C%0Ax%5E2%2Bx-4%3D0%5C%5C%0A%5CDelta%3D1%5E2-4%5Ccdot1%5Ccdot%28-4%29%3D1%2B16%3D17%5C%5C%0Ax_1%3D%5Cdfrac%7B-1-%5Csqrt%7B17%7D%7D%7B2%7D%5C%5C%0Ax_2%3D%5Cdfrac%7B-1%2B%5Csqrt%7B17%7D%7D%7B2%7D%5C%5C%5C%5C%0A%5Cdisplaystyle%0AV%3D%5Cpi%5Cint%5Climits_0%5E%7B%5Cdfrac%7B-1%2B%5Csqrt%7B17%7D%7D%7B2%7D%7D%284-x%5E2-x%29%5E2%5C%2Cdx%5C%5C%0AV%3D%5Cpi%5Cint%5Climits_0%5E%7B%5Cdfrac%7B-1%2B%5Csqrt%7B17%7D%7D%7B2%7D%7D%2816-4x%5E2-4x-4x%5E2%2Bx%5E4%2Bx%5E3-4x%2Bx%5E3%2Bx%5E2%29%5C%2Cdx%5C%5C%0AV%3D%5Cpi%5Cint%5Climits_0%5E%7B%5Cdfrac%7B-1%2B%5Csqrt%7B17%7D%7D%7B2%7D%7D%28x%5E4%2B2x%5E3-7x%5E2-8x%2B16%29%5C%2Cdx%5C%5C%0AV%3D%5Cpi%20%5Cleft%5B%5Cdfrac%7Bx%5E5%7D%7B5%7D%2B%5Cdfrac%7Bx%5E4%7D%7B2%7D-%5Cdfrac%7B7x%5E3%7D%7B3%7D-4x%5E2%2B16x%5Cright%5D_0%5E%7B%5Cdfrac%7B-1%2B%5Csqrt%7B17%7D%7D%7B2%7D%7D%5C%5C%0A)
The rest of solution in the attachment.
There's a mistake in the picture
It shoud be
