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oee [108]
3 years ago
15

A sales associate in a shoe store earns $325 per week, plus a commission equal to 4% of her sales. This week her goal is to earn

at least $500. What is the minimum dollars' worth of shoes she must sell in order to reach her goal? Show the inequality and steps to solve.
Mathematics
1 answer:
Vesnalui [34]3 years ago
8 0

The inequality would be 500 ≥ 325 + 0.04x

Steps to solve the inequality:

Subtract 325 from each side:

175 ≥ 0.04x

Divide both sides by 0.04:

x ≥ 175 / 0.04

x ≥ $4,375

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3 years ago
Write a function in any form that would match the graph shown below
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Pick whichever form you prefer.

=============================================================

Explanation:

The vertex is the highest point in this case, which is located at (1,8).

In general, the vertex is (h,k). So we have h = 1 and k = 8.

One root of this parabola is (-1,0). So we'll plug x = -1 and y = 0 in as well. As an alternative, you can go for (x,y) = (3,0) instead.

Plug those four values mentioned into the equation below. Solve for 'a'.

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7 0
2 years ago
There are 10 employees in a particular division of a company. Their salaries have a mean of 570,000, a median of $55,000,and a s
harkovskaia [24]

Answer:

a) $160,000

b) $55,000

c) $332264.804

Step-by-step explanation:

We are given that there are 10 employees in a particular division of a company and their salaries have a mean of $70,000, a median of $55,000, and a standard deviation of $20,000.

And also the largest number on the list is $100,000 but By accident, this number is changed to $1,000,000.

a) Value of mean after the change in value is given by;

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       \frac{\sum X}{n} = $70,000  ⇒ \sum X = 70,000 * 10 = $700,000

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  Therefore, New mean = \frac{1600000}{10} = $160,000 .

b) Median will not get affected as median is the middle most value in the data set and since $1,000,000 is considered to be an outlier so median remain unchanged at $55,000 .

c) Original Variance = 20000^{2} i.e.  20000^{2} = \frac{\sum x^{2} - n*xbar }{n -1}

    Original \sum x^{2} = (20000^{2} * (10-1)) + (10 * 70,000) = $3,600,700,000

    New \sum x^{2} = $3,600,700,000 - 100,000^{2} + 1,000,000^{2} = 9.936007 * 10^{11}  

    New Variance = \frac{new\sum x^{2} - n*new xbar }{n -1} = \frac{9.936007 *10^{11}  - 10*160000 }{10 -1} = 1.103999 * 10^{11}    Therefore, standard deviation after change = \sqrt{1.103999 * 10^{11} } = $332264.804 .

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3 years ago
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