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oee [108]
3 years ago
15

A sales associate in a shoe store earns $325 per week, plus a commission equal to 4% of her sales. This week her goal is to earn

at least $500. What is the minimum dollars' worth of shoes she must sell in order to reach her goal? Show the inequality and steps to solve.
Mathematics
1 answer:
Vesnalui [34]3 years ago
8 0

The inequality would be 500 ≥ 325 + 0.04x

Steps to solve the inequality:

Subtract 325 from each side:

175 ≥ 0.04x

Divide both sides by 0.04:

x ≥ 175 / 0.04

x ≥ $4,375

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1) AU (C - B) =
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Answer:

A \cup (C-B) = (A \cup C) \cap  (A \cup B^c)\\A \cup (B \cap C) = (A \cup B) \cap (A \cup C) \,\,\, \text{Here you use double inclusion.}\\A \cup B \cup C =  A \cup (B \cup C)\\B^c \cap (A-C)  = (B^c - C) \cap A\\(B \cap C) - A = (B-A)\cap C\\C-(A\cup B) =  (C - A )\cap B\\A^c \cap (B \cap C) = ( A^c \cap B) \cap C

Step-by-step explanation:

A \cup (C-B) = A \cup (C \cap B^c) = (A \cup C) \cap  (A \cup B^c)\\A \cup (B \cap C) = (A \cup B) \cap (A \cup C) \,\,\, \text{Here you use double inclusion.}\\A \cup B \cup C = (A \cup B ) \cup C  = A \cup (B \cup C)\\B^c \cap (A-C)  = B^c \cap (A \cap C^c) =  (B^c \cap C^c) \cap A =  (B^c - C) \cap A\\(B \cap C) - A = (B \cap C) \cap A^c  = (B \cap C) \cap A^c = (B \cap A^c)\cap C = (B-A)\cap C\\C-(A\cup B) = C \cap (A\cup B)^c = C \cap (A^c \cap B^c ) = (C  \cap A^c )\cap B^c = (C - A )\cap B\\

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