The diffusion time of the red blood cell to take oxygen through the membrane is 25uS.
The small capillaries in the lungs are in close contact and it takes a red blood cell 0.5 seconds to squeeze through the capillary.
The diffusion time for the oxygen across the 1 um thick membrane separating the air is given by,
t = x²/2D
Where,
t is the diffusion time,
x is the thickness of the membrane,
D is the diffusion coefficient.
Putting values,
t = (1 x 10⁻⁹)²/2 x 2 x 10⁻¹¹
t = 10⁻⁷/4
t = 25 x 10⁻⁹ seconds.
t = 25 uS.
so, the diffusion time is 25uS.
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The number is -45 (negative 45)
The value of the function (f.h)(x) is 96x⁵ + 132x⁴ + 78x³ + 18x²
<h3>How to solve function?</h3>
f(x) = 3x² + 4x³ + 8x⁴
g(x) = -3x + 12x² - 5x³
h(x) = 12x + 6
Therefore,
(f.h)(x) = f(x).h(x)
Hence,
f(x).h(x) = (3x² + 7x³ + 8x⁴)(12x + 6)
f(x).h(x) = 36x³ + 18x² + 84x⁴ + 42x³ + 96x⁵ + 48x⁴
(f.h)(x) = 96x⁵ + 84x⁴ + 48x⁴ + 36x³ + 42x³ + 18x²
(f.h)(x) = 96x⁵ + 132x⁴ + 78x³ + 18x²
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