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Gennadij [26K]
4 years ago
12

T diagram between two cars and the models

Mathematics
1 answer:
Temka [501]4 years ago
5 0
Make a t diagram between two cars
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Complete the statement with , or =.
Natalija [7]

Step-by-step explanation:

Hey there!

0.3 = 3/8 (equal to eachother)

Reason: (<u>3</u><u>/</u><u>8</u><u> </u><u>=</u><u> </u><u>0.375</u><u>)</u>

<u>So</u><u>,</u><u> </u><u>0</u><u>.</u><u>3</u><u> </u><u>is</u><u> </u><u>equal</u><u> </u><u>to</u><u> </u><u>eachother</u><u>. </u>

<u>0</u><u>.</u><u>3</u><u>=</u><u>0</u><u>.</u><u>3</u>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

7 0
4 years ago
What is the surface area of a cube if the cube has a base of 10ft, 10ft, 10ft
nadezda [96]
600 ft^2
Find the area of one face by multiply 10x10 which equals 100, then multiply that by the number of faces of a cube:6
100*6=600
6 0
3 years ago
Square root of 32-6√15​
BlackZzzverrR [31]

Answer:

8 . 76209992276

Step-by-step explanation:

does this help

5 0
3 years ago
The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0
3 years ago
Explain how you got the answer(:
Natali [406]
Hey there :) I'm pretty sure that your answer is D) ∠S ≅ <span>∠Y because corresponding angles of similar triangles are congruent.

I think that it is the answer because if you shift your paper around, and look at the angles from different views, you can tell that angles S and Y are congruent, or the same, because of the way that both angles are at the end of the longer sides of both triangles.

So, your answer is D!

~Hope this helped!~</span>
8 0
3 years ago
Read 2 more answers
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