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Gennadij [26K]
3 years ago
12

T diagram between two cars and the models

Mathematics
1 answer:
Temka [501]3 years ago
5 0
Make a t diagram between two cars
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1. Subtract. 9 1/3-1 2/3 = ? Explain how you got the answer.
AleksAgata [21]
My answer is 8 5/9
First, you have to multiply the denominators to get your least common denominator.
Second, you have to multiply the numerators and the denominators together to get two different fractions with the same denominator. You should get 9 3/9 and 1 6/9.

Your answer should be 8 5/9
8 0
3 years ago
QUICK! WHAT IS THIS ANSWER?
FromTheMoon [43]

Answer:

a)2x-3y

b)4(9a-4)

Step-by-step explanation:

<h3>a)</h3>

we want to expand the following expression:

\displaystyle -   \frac{1}{4} ( - 8x + 12y)

well to do so we consider distributive property thus distribute:

\displaystyle -   \frac{1}{4} (- 8x )+  -  \frac{1}{4}( 12y)

reduce fraction which yields:

\displaystyle -   \frac{1}{4} (- 8x )+  -  \frac{1}{4}( 12y) \\  \\  \displaystyle 2x + ( - 3y)

simplify Parentheses:

\displaystyle \boxed{ 2x - 3y}

<h3>b)</h3>

in the expression there's a common factor of 4 therefore factor it out:

\displaystyle 9.4a - 4.4 \\  \\  \displaystyle   \boxed{4(9a - 4)}

3 0
3 years ago
Write an equation of the ellipse with foci at (0,+12) and vertices at (0,+13)
Musya8 [376]

Answer:

Quadratic relations and comic sections unit test part 1

10. b. x^2/25 + y^2/169 =1

Step-by-step explanation:

7 0
3 years ago
Has endpoints J(13, 8) and K(–6, –6). Find the coordinates of the midpoint of .
vova2212 [387]

Answer:

the midpoint of it is 8,-6

Step-by-step explanation:

rhgsr egh

3 0
3 years ago
PLEASE HELP!!! So the answer I got was 19.14 however that is not the correct answer. How do I solve this problem. Not sure what
Mamont248 [21]

Check the picture below.

so we know the radius of the semicircle is 2 and the rectangle below it is really a 4x4 square, so let's just get their separate areas and add them up.

\stackrel{\textit{area of the semicircle}}{\cfrac{1}{2}\pi r^2}\implies \cfrac{1}{2}(\stackrel{\pi }{3.14})(2)^2\implies 3.14\cdot 2\implies 6.28 \\\\\\ \stackrel{\textit{area of the square}}{(4)(4)}\implies 16 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{sum of both areas}}{16+6.28=22.28}~\hfill

3 0
3 years ago
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