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zloy xaker [14]
2 years ago
11

Suppose you open a bank account. Every month you deposit $40. Write an equation that relates the total number of dollars deposit

ed, T , and the month, m.
Mathematics
1 answer:
alekssr [168]2 years ago
4 0
$40=T >?=m 
 
T= $40,$80,$120,etc.
m=1,2,3,etc
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Read and write the number in two other forms 65,058
Vlad [161]
60,000+ 5,000 + 50 + 8 and sixty five thousand fifty eight
5 0
2 years ago
Read 2 more answers
Lauren's scores on her math tests are, 93, 91, 98, 100, 95, 92 , and 96. What score could Lauren get on he next math test so tha
Ugo [173]
First you need to find the mean & median:
mean:
93 + 91 + 98 + 100 + 95 + 92 + 96 = 665
665 / 7 = 95
median:
<u>91</u>, <em>92</em>, <u>93</u>, 95, <u>96</u>, <em>98</em>, <u>100</u>
95

Because the mean and median are the same, her next test score should be 95. The average of the current average and 95 (her next test score) is 95, so that will remain the same. If you add 95 to the median list,the median will still be 95. The same goes for the mean.Her next test score should be 95.
7 0
3 years ago
Find the horizontal and vertical asymptotes of​ f(x). ​f(x) equals = StartFraction 6 x Over x plus 2 EndFraction 6x x+2 Find the
miss Akunina [59]

Answer:

The horizontal asymptote can be described by the line y = 6

The vertical asymptote can be described by the line x = -2

Step-by-step explanation:

* <em>Lets the meaning of vertical and horizontal asymptotes</em>

- <u><em>Vertical asymptotes</em></u> are vertical lines which correspond to the zeroes

  of the denominator of a rational function

- <u><em>A horizontal asymptote</em></u> is a y-value on a graph which a function

 approaches but does not actually reach

- If the degree of the numerator is less than the degree of the

 denominator, then there is a horizontal asymptote at y = 0

- If the degree of the numerator is greater than the degree of the

 denominator, then there is no horizontal asymptote

- If the degree of the numerator is equal the degree of the denominator,

 then there is a horizontal asymptote at y = leading coefficient of the

 numerator ÷ leading coefficient of the denominator

* <em>Lets solve the problem</em>

∵ f(x)=\frac{6x}{x+2}

∵ The numerator is 6x

∵ The denominator is x + 2

∴ The numerator and the denominator have same degree

∵ The leading coefficient of the numerator is 6

∵ The leading coefficient of the denominator is 1

∴ There is a horizontal asymptote at y = 6/1

∴ <em>The horizontal asymptote can be described by the line y = 6</em>

- Put the denominator equal zero to find its zeroes

∵ The denominator is x + 2

∴ x + 2 = 0

- Subtract 2 from both sides

∴ x = -2

∴ <em>The vertical asymptote can be described by the line x = -2</em>

6 0
3 years ago
Read 2 more answers
PLEASE I NEED HELP IM SO CONFUSED, ILL GIVE BRAINLIEST AND 5 STARS AND HEART IF CORRECT
ella [17]

Answer:

im pretty sure the ones that say "if not replaced" are independant, sorry if im wrong but im trying to help you out :)

Step-by-step explanation:

7 0
2 years ago
If the point (a,3) lies on the graph of the equation 5x + y = 8, then a=<br>a.01<br>b.0-1<br>c.0-7​
fomenos

Answer:

A (a = 1)

Step-by-step explanation:

A coordinate point is always in the form (x,y) that means the first point is always x-coordinate and the second point is always y-coordinate.

The equation given is:

5x + y = 8

The point is (a,3), so that means x = a and y = 3

We substitute the values into the equation and find a. Shown below:

5x + y = 8

5(a) + (3) = 8

5a + 3 = 8

5a = 8 - 3

5a = 5

a = 5/5

a = 1

Answer choice A is right

6 0
3 years ago
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