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Flura [38]
3 years ago
15

Which technique is most appropriate to use to solve each equation?

Mathematics
1 answer:
AfilCa [17]3 years ago
6 0

(x+3)(x+2)=0 ↔ zero product property and

(x+3)(x+2)=0 ↔ square root property.

Solution:

Given expressions are (x+3)(x+2)=0 and x^{2}+6=31.

To find which techniques is most appropriate to solve each equation.

Equation 1: (x+3)(x+2)=0

Zero product property states that if AB = 0 then A = 0 or B = 0.

In the equation is (x+3)(x+2)=0, zero product property is used to solve the equation.

(x + 3) = 0 (or) (x + 2) = 0

x = –3 (or) x = –2

Equation 2: x^{2}+6=31

Subtract 6 from both sides of the equation.

x^{2}+6-6=31-6

x^{2}=25

x^{2}=5^2

Take square root on both sides of the equation.

x = 5

Square root property is used to solve the equation.

Hence (x+3)(x+2)=0 ↔ zero product property and

(x+3)(x+2)=0 ↔ square root property.

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