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RSB [31]
2 years ago
9

Which line is a graph of the equation x = –6?

Mathematics
1 answer:
vaieri [72.5K]2 years ago
8 0

Answer:

The correct line is Line A.

Step-by-step explanation:

The answer is a vertical line to the left for two reasons.

1) all x = a number equations will always make a vertical line.

2) And the negative portion of that graph would be on the left.

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A camp ground consists of 12 square campsites arranged in a line along a beach. The distance from the edge of a campsite to the
Darina [25.2K]
X=side length of a campsite
12x(5+x)=1248  because each campsite has a length of x and there are 12                           and from the top of the camp to the water is the 5 yds + a                             side length and LW=1248
60x+12x^2=1248
12x^2+60x-1248=0
x^2+5-14=0
(x+7)(x-2)=0
x+7=0 or x-2=0
x=-7 or x=2
x=2 because width can't be negative
the width of one campsite is 2 yds
4 0
3 years ago
Find the measure of the acute angles pls help
tangare [24]

Answer:

60 degrees

and

52 degrees

6 0
3 years ago
16. Solve -3x2 - 9x + 12 = 0.
AURORKA [14]

Given :

  • -3x² - 9x + 12 = 0

To find :-

  • Value of x .

Solution :-

Given equation ,

  • -( 3x² + 9x -12 ) = 0
  • 3x² + 9x - 12 = 0
  • 3x² + 12x - 3x - 12 = 0
  • 3x ( x +4) -3( x +4) = 0
  • (3x -3)(x +4) = 0
  • x = 3/3 , -4
  • x = 1 , -4
7 0
2 years ago
Tell whether (1,6) is a solution of y = x + 7
andrezito [222]

Answer:

no it is not a solution.READ THE WHOLE EXPLANATION! IT WILL HELP WITH THE OTHER PROBLEMS!!!!

Step-by-step explanation:

when something like (1,6) is written consider it as (x,y). in this case, 1 is considered as x, and 6 is considered as y. if you substitute these number for x and x and y, (x =1 and y =6), you'll see that the equation will go from y=x +7, to 6=1+7. Which is not true.

5 0
3 years ago
Read 2 more answers
2x2 - 12x + 10<br>what are the roots​
Tcecarenko [31]

Answer:

5 & 1

Step-by-step explanation:

We can use the quadratic formula to solve this:

Quadratic Formula = \frac{-b+-\sqrt{b^2-4ac} }{2a}

So we will have 2 answers (roots).

a is the coefficient of x^2 (2)

b is the coefficient of x (-12)

c is the constant (10)

Now, substituting, we get:

x = \frac{-b+-\sqrt{b^2-4ac} }{2a}=\frac{12+-\sqrt{(-12)^2-4(2)(10)} }{2(2)}=\frac{12+-\sqrt{64} }{4}=\frac{12+-8}{4}=\frac{12+-8}{4}=5,1

Hence the roots are 5 & 1

4 0
3 years ago
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