I really need help pls.

Mathematics

1 answer:

Zigmanuir [339]3 years ago

7 0

Because if you look across from it its 7.

You might be interested in

If m1+m4=70 find the sum of 6+7

Natasha_Volkova [10]

290 degrees is your answer :)

4 0

3 years ago

Read 2 more answers

Please help I am stuck at 34 points I need atleast an 80 by today!!

Ostrovityanka [42]

Answer:

12 mi

Step-by-step explanation:

5 0

3 years ago

Please answer this problem I really don't get it.

Helen [10]

It’s the sams equation, just negative cause it’s reflected on the x-axis

4 0

3 years ago

Represent the set of numbers as decimals on the number line {5 3/10, 5 1/10, 5 and if you answer more than needed thank you

Alina [70]

Answer:

(0.53 > 0.51) both less than 1 while 5 is greater than both

Step-by-step explanation:

$\frac{53}{10} = .53, \frac{51}{10} = .51.$ and 5

the number line has two sides, with the left side for negative numbers while the right side is for positive numbers.

-5 -4 -3 -2 -1 -.53 -.51 0 .51 .53 1 2 3 4 5

By studying the number line above all decimal numbers greater than 0 but less than 1 are from 0, .1, .2,.........,.98, .99, 1.00 which is also the same as 1 because all numbers greater than 1 has an invisible point at its right side like 2., 3. which also means 2, 3 while negative number are all less than 0

7 0

3 years ago

Evaluate cos(sin^-1(4/5)

PSYCHO15rus [73]

Step-by-step explanation:

$Let \: \: \theta = \sin^{ - 1} (\frac{4}{5}) \\ \\ \therefore \: \sin\theta = \frac{4}{5} \\ \\ \because \: { \cos}^{2} \theta =1 - { \sin}^{2} \theta \\ \\ \therefore \: { \cos}^{2} \theta = 1 - (\frac{4}{5} )^{2} \\ \\ = 1 - \frac{16}{25} \\ \\ = \frac{25 - 16}{25} \\ \\ = \frac{9}{25} \\ \\ \therefore \:{ \cos}\theta = \pm \: \frac{3}{5} \\ \\ \because \: \theta \: lie \: in \: the \: first \: quadrant \\ \\ \therefore \: { \cos}\theta = \: \frac{3}{5} \\ \\ \implies \theta = { \cos}^{ -1 } \: \frac{3}{5}\\\\\implies \theta = { \cos}^{ -1 } \: \frac{3}{5}= { \sin}^{ -1 } \: \frac{4}{5} \\ \\ \therefore \: \cos( \ {sin}^{ - 1} \frac{4}{5} ) \\ \\ = \cos( \ {cos}^{ - 1} \frac{3}{5} ) \\\\ = \frac{3}{5} \\ \\ \purple{ \boxed{\therefore \: \cos( \ {sin}^{ - 1} \frac{4}{5} ) = \frac{3}{5}}}$

8 0

3 years ago