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3 years ago

A square has an area of 4 ft^2 what is the lenght of each side

Mathematics

1 answer:

sergiy2304 [10]3 years ago

5 0

area of square = 4ft²

a s area of square = length×lenght

let lenght =x

so area = x²

x²= 4ft²

taking square root

x=2 ftSo lebght of each side is 2 ft.

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A normal distribution has a mean of 60 and a standard deviation of 2. Determine the z-

a_sh-v [17]

Answer: z score is -19

Work Shown:

x = 22 is the raw score

mu = 60 is the mean

sigma = 2 is the standard deviation

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z = -38/2

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3 years ago

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kirill115 [55]

Answer:

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Step-by-step explanation:

Given that:

Height of dog when it was a puppy = $5\frac{1}{2}$ inches

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It means that we will add this height in the height of dog when it was a puppy.

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Hence,

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7 0

3 years ago

A barrel had 20 liters of water. Water leaked out from the barrel at a constant rate. After 24 hours, 14 liters of water was lef

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4 years ago

Use the squared identities to simplify 2sin^2xsin^2x

nataly862011 [7]

Answer:

option A

Step-by-step explanation:

cos(4x) = cos(2x+2x) = cos(2x)*cos(2x) - sin(2x)*sin(2x)

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cos(4x) = cos^2(2x) - cos^2(2x) - 1 (using cos^2(2x) + sin^2(2x) = 1)

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cos(2x) = cos^2(x) - sin^2(x)

cos(2x) = 1 - sin^2(x) - sin^2(x) (using cos^2(x) + sin^2(x) = 1)

cos(2x) = 1 - 2sin^2(x) (eq. 2)

Replacing eq. 2 into eq. 1:

cos(4x) = 2[1 - 2sin^2(x)]^2 - 1

cos(4x) = 2[1 - 4sin^2(x) + 4sin^4(x)] - 1

cos(4x) = 1 - 8sin^2(x) + 8sin^4(x)

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Using eq. 2:

2sin^2(x)sin^2(x) = cos(4x)/4 - 1/4 + 1 - cos(2x)

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3 years ago

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elena-14-01-66 [18.8K]

Answer:

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Step-by-step explanation:

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3 years ago