The solution of x is x = 0, x =2 and x = -5
<h3>How to solve for the unknown?</h3>
The equation is given as:
2x^3+6x^2-20x=0
Factor out x
x(2x^2+6x-20)=0
Split the equation
x = 0 or 2x^2+6x - 20=0
Solve for x in 2x^2+6x - 20=0
Expand the equation
2x^2 + 10x - 4x - 20 = 0
Factorize the equation
(2x - 4)(x +5) = 0
Split the equation
2x - 4 = 0 and x + 5 = 0
Solve for x
x =2 and x = -5
Hence, the solution of x is x = 0, x =2 and x = -5
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Answer:
5555555
Step-by-step explanation:
I really dont know
Plug the 3 in for x because x=3 so it’ll be 6(3)+7 and that equals 25
Answer:
Well, "b" is just a variable. It's not really the function. I'm not quite sure what your asking. It can't be 1 because it can't. Math was founded on these mathematical laws. Consider talking to your teacher about this for further explanation.
Step-by-step explanation:
