Answer:
True, see proof below.
Step-by-step explanation:
Remember two theorems about continuity:
- If f is differentiable at the point p, then f is continuous at p. This also applies to intervals instead of points.
- (Bolzano) If f is continuous in an interval [a,b] and there exists x,y∈[a,b] such that f(x)<0<f(y), then there exists some c∈[a,b] such that f(c)=0.
If f is differentiable in [0,4], then f is continuous in [0,4] (by 1). Now, f(0)=-1<0 and f(4)=3>0. Thus, we have the inequality f(0)<0<f(4). By Bolzano's theorem, there exists some c∈[0,4] such that f(c)=0.
Answer:
-5/ (x^19 * y^12)
Step-by-step explanation:
-15x^-10 * y ^ -3 * x^-9 * y^-9/3 (It's writing it like this.)
15 and 3 have a GCF of 3.
-5x^-10 * y^-3 * x^-9 * y^-9/1
Reduce similar occurrences. *twice in a row*
-5x^(-10 + (-9)) * y^(-3 + (-9))/1
Remove extra signs *twice in a row*
-5x^(-10 - 9) * y^(-3 - 9)/1
Remove extraneous 1.
-5x^(-10 - 9) * y^(-3 - 9)
Add integers.
-5x^-19 * y^-12
Negative powers change multiplication to division.
-5 / (x^19 * y^12) is the final answer.
Even with that, the simplified answer wouldn't have negative exponents because of the negative powers rule.
Perimeter = (20 + 2x) mm.
Step-by-step explanation:
The octopus pupil has length 20 mm and the expression for its area is given by (20x - 200) square mm.
If the width of the octopus pupil is w, then 20w = 20x - 200
⇒ w = (x - 10) mm.
Therefore, the expression for its perimeter is 2(Length + Width) = 2 ( 20 + x - 10) = 2( 10 + x) = (20 + 2x) mm. (Answer)
Square root means 46225^1/2 so the answer is 65
