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Shalnov [3]
3 years ago
9

Plz help i cant slove it

Mathematics
1 answer:
Lana71 [14]3 years ago
7 0

Answer:x=30

Step-by-step explanation:

So first you have to find x so add all your sides together:

Equation: 45+2x+0.5x+x=150

Combine like terms: 45+3.5x=150

Subtract 45 from -45 -45

both sides: 3.5x=105

Then divide by 3.5: x=30

Now that you have your x substitute it in:

2(30)=60

0.5(30)=15

and the last one is x=30

And there you have all your sides! If you wanna check it just add up all the sides and it should equal 150.

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Write the equation g(x) in vertex form of a
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The equation g(x) in vertex form of a  quadratic function for the transformations  whose graph is a  translation 4 units left and 1 unit up of the  graph of f(x) is (x-4)² + 1

Given a  quadratic function for the transformations given  the function f(x) = x²

If the function g(x) of the graph is translated 4 units to the left, the equation becomes (x-4)² (note that we subtracted 4 from the x value

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Answer:

see below

Step-by-step explanation:

\frac{x-1}{x^2-3x+2}+ \frac{x-2}{x^2-5x+6} +\frac{x-5}{x^2-8x+15}

we need to simplify that

x^2-3x+2=(x-1)(x-2)\\\\x^2-5x+6=(x-2)(x-3)\\\\x^2-8x+15=(x-3)(x-5)

so we can continue

\frac{x-1}{(x-1)(x-2)}=\frac{1}{x-2}\\\\\frac{x-2}{(x-2)(x-3)} =\frac{1}{x-3}\\\\\frac{x-5}{(x-3)(x-5)} =\frac{1}{x-3}

and we can put all together

\frac{1}{x-2}+ \frac{1}{x-3}+ \frac{1}{x-3}\\\\\frac{1}{x-2} +\frac{2}{x-3}\\\\\frac{x-3}{(x-3)(x-2)}+ \frac{2(x-2)}{(x-2)(x-3)} \\\\\frac{x-3+2x-4}{(x-3)(x-2)}\\\\\frac{3x-7}{x^2-5x+6}

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