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2 years ago

Plz help i cant slove it

Mathematics

1 answer:

Lana71 [14]2 years ago

7 0

Answer:x=30

Step-by-step explanation:

So first you have to find x so add all your sides together:

Equation: 45+2x+0.5x+x=150

Combine like terms: 45+3.5x=150

Subtract 45 from -45 -45

both sides: 3.5x=105

Then divide by 3.5: x=30

Now that you have your x substitute it in:

2(30)=60

0.5(30)=15

and the last one is x=30

And there you have all your sides! If you wanna check it just add up all the sides and it should equal 150.

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Advocard [28]

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Step-by-step explanation:

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Probability:

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5 0

2 years ago

The angle marked a = 75°. Work out the value of x. The diagram is not drawn accurately.

NikAS [45]

Answer:

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Step-by-step explanation:

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olganol [36]

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2 years ago

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3 years ago

Lim t^4 - 6 / 2t^2 - 3t + 7

Harman [31]

I think you meant to say

$\displaystyle \lim_{t\to2}\frac{t^4-6}{2t^2-3t+7}$

(as opposed to x approaching 2)

Since both the numerator and denominator are continuous at t = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

$\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}$

Because these expressions are continuous at t = 2, we can compute the limits by evaluating the limands directly at 2:

$\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}$

6 0

2 years ago