All categories

1 year ago

Use the given figure to complete the statement below. is the bisector of ∠COA.

Mathematics

1 answer:

zhannawk [14.2K]1 year ago

8 0

You didn't give us the picture but here's some info on bisectors

An angle bisector of a triangle is a segment, ray or line which divides an angle of the triangle into two congruent (equal in measure) parts. Since all triangles have three angles, all triangles have three angle bisectors.

The three angle bisectors of the angles of a triangle meet in a single point, called the incenter . Here, I is the incenter of ΔPQR . The incenter is equidistant from the sides of the triangle. That is, PI=QI=RI .

Hope this helps till you put a picture!

You might be interested in

I need 1-5 and 8 and 9 solved

meriva

Answer:

1. A

2. H

3.B

4. H

5. A

Those are the answers

Step-by-step explanation:

1. 30 - 2(-8)= 46

2. BODMAS applied 6-7 =-1

3. 45/-5=-9

4. Sum is h +73

5.BODMAS applied 60 /6 = 10

8 0

2 years ago

PLEASE HELP ASAP

lesya692 [45]

Answer:

x^2+14x+49 ( it could be polynomial because it has 3 terms and each term has a whole number and a coefficient)

Step-by-step explanation:

(x+7)^2

(x+7)(x+7)

x^2+7x+7x+49

x^2+14x+49

I am not sure it's a polynomial or not

7 0

3 years ago

Need help with 2 math questions pls help me for 20 points.

s344n2d4d5 [400]

The answers are A and B

7 0

2 years ago

) f) 1 + cot²a = cosec²a

notsponge [240]

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).

$\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}$

csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.

$\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}$

Another identity is:

$\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}$

Therefore:

$\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}$

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

$\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}$

Another identity:

$\displaystyle \large{\sin^2x+\cos^2x=1}$

Therefore:

$\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}\longrightarrow \boxed{ \frac{1}{\sin^2x}={\frac{1}{\sin^2x}}}$

Hence proved, this is proof by using identity helping to find the specific identity.

6 0

2 years ago

On a business trip, Jon must drive from his office to a clients's office, a distance of 216 miles. He sets off a 8 a.m. Suppose

chubhunter [2.5K]

Answer:

b.) f(t) = 216 - 66t

Step-by-step explanation:

Since we consider t and time travelled in hours and we are given that the average speed of Jon is 66mph, then we can calculate the distance travelled at any point in time by Jon.

Distance = Speed * time.

Distance = 66 * t = 66t.

Since total distance from clients house 216 miles and distance travelled by Jon at any point in time is 66t, then remaining distance to be covered from the clients house, that is distance between Jon and the clients house becomes:

Distance from client house = 216 - 66t.

3 0

2 years ago