Temperature at noon: Tn=-2.9 f
Rate: r=+1.3 f/h
Total decreased: d=-3.7 f
Temperature at midnight: Tm=?
Tm=Tn+r(6 p.m.-12 m)+d
Tm=-2.9 f+(1.3 f/h)(18 h-12 h)+(-3.7 f)
Tm=-2.9 f+(1.3 f/h)(6 h)-3.7 f
Tm=-2.9 f+7.8 f-3.7 f
Tm=1.2 f
Answer: T<span>he temperature at midnight was 1.2 f</span>
Answer:
3.260 is greater.
Step-by-step explanation:
The ones place is the same, the tenths place is the same, the hundredths place is different. 3.260 has a greater hundredths place, so 3.260 > 3.206
Answer:
The solution is given in the pictures below
Step-by-step explanation:
Using the graph, it is found that 976 passengers had carry-on luggage that weighed less than 20 lb.
<h3>Graph:</h3>
The graph is not given in this problem, but an internet search indicates that the information it contains is as follows:
- 120 passengers carry luggage of 4 lb or less.
- 222 passengers carry luggage between 5 lb and 9 lb.
- 378 passengers carry luggage between 10 lb and 14 lb.
- 256 passengers carry luggage between 15 lb and 19 lb.
- 90 passengers carry luggage between 20 lb and 24 lb.
- 40 passengers carry luggage between 25 lb or more.
Hence, the number of passengers with luggage below 20 lb is:

976 passengers had carry-on luggage that weighed less than 20 lb.
A similar problem, also involving the use of graph, is given at brainly.com/question/25836450