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sineoko [7]
3 years ago
8

Use cubic regression to find a function that fits the following points.

Mathematics
2 answers:
8090 [49]3 years ago
8 0

Answer:

y = 2x³ + x² - 4x + 6

Step-by-step explanation:

General formula:

y = ax³ + bx² + cx + d

If you replace point (0, 6) in the general formula, you get:

6 = a(0)³ + b(0)² + c(0) + d

6 = d

If you replace points (-1, 9), (1, 5) and (2, 18) in the general formula, you get the following system of equations:

9 = a(-1)³ + b(-1)² + c(-1) + 6

9 = -a + b - c + 6     (eq. 1)

5 = a(1)³ + b(1)² + c(1) + 6

5 = a + b + c + 6     (eq. 2)

18 = a(2)³ + b(2)² + c(2) + d

18 = 8a + 4b + 2c + 6     (eq. 3)

Adding equation 1 to equation 2:

14 = 2b + 12

(14 - 12)/2 = b

b = 1

Multiplying equation 1 by 2:

18 = -2a + 2b - 2c + 12     (eq. 4)

Adding equation 4 to equation 3, and replacing with b value:

36 = 6a + 6b + 18

36 = 6a + 6 + 18

(36 - 6 - 18)/6 = a

a = 2

Replacing a and b values in equation 1:

9 = -2 + 1 - c + 6

c = -2 + 1 + 6  - 9

c = -4

Fynjy0 [20]3 years ago
7 0

Answer:

y = ax³ + bx² +cx +d (Main eq.)

Solve for a, b, c and d.

Solution:

y = 2x³ + x² -4x +6

Step-by-step explanation:

i) Solving for d:

Given point (0,6), at this point your x value is 0 and your y value is 6. Substitute the values on the Main Eq. above and you will find the d value to be 6.

ii) Solving for a, b & c.

Using points (-1,9),(1,5) and (2,18)

Substitute the given points on the Main Eq. above and you will have 3 equations with 3 unknown variables and solve the equations simultaneously to find your a, b & c.

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Slav-nsk [51]

Answer:

6 ft

Step-by-step explanation:

As we know that, the arch meet the ground are the value of x when y = 0

y=−0.9(x+3)(x−3)

<=> 0 = −0.9(x+3)(x−3)

<=> x=3 or x=-3  

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7 0
3 years ago
Find the slope and y-intercept of the line.
balandron [24]

Answer:

D

Step-by-step explanation:

Slope = (y2 - y1) / (x2 - x1)

= (2 - 0) / (0 - (-3)

= 2/3

Y intercept 2

4 0
3 years ago
Does the table represent an exponential function?
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6 0
3 years ago
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8 0
3 years ago
What is the rate of change and initial value for the linear relation that includes the points shown in the table?
Wittaler [7]

Answer:

Initial value 12, rate of change: -2

Step-by-step explanation:

Step 1

Find the rate of change

we know that

In a linear equation the rate of change is equal to the slope

The formula to calculate the slope between two points is equal to  

m=\frac{y2-y1}{x2-x1}  

we have

A(1,10)\ B(2,8)  

Substitute the values  

m=\frac{8-10}{2-1}

m=-2  ----> rate of change

Step 2

Find the initial value

The equation of  the line into slope-point form is equal to

y-y1=m(x-x1)

Substitute

y-10=-2(x-1)

y=-2x+2+10y=-2x+12

The initial value is the value of y when the value of x is equal to zero (is the y-intercept)

y=-2*0+12=12----> initial value

7 0
3 years ago
Read 2 more answers
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