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3 years ago

2/3(6c+4)-(8c-5)

Mathematics

1 answer:

Butoxors [25]3 years ago

8 0

Answer:

Your answer is: $-4c+23/3$

Simplify the expression.

Step-by-step explanation:

Hope this helped : )

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A runner’s goal is to complete a mile in 4 minutes or less. The runner’s speed is 20 feet per second. Does the runner meet the g

Scilla [17]

Answer:

no, because the runner is short by 480 feet

Step-by-step explanation:

there are 5280 feet in 1 mile

5280 feet= 1 mile 20 feet= 1 second (times by 240)

4800 feet= 240 seconds

he is 5280-4800= 480 feet less

please give me brainliest!!<3

3 0

3 years ago

A cable runs along the wall from C to P at a cost of $4 per meter, and straight from P to M at a cost of $5 per meter. If M i

a_sh-v [17]

Answer:

The minimum cost of installing the cable is $156.

Step-by-step explanation:

We have an optimization problem.

We have to minimize the cost of the cable.

We will use the variable x to express the the length of cable CP and PM, accordingly to the attache picture.

The length of the cable that goes from C to P (let's call it CP) is x.

$\bar{CP}=x$

Then, the length of the cable that goes from P to M (PM) can be calcualted usign the Pithagorean theorem:

$\bar{PM}=\sqrt{(33-x)^2+9^2}$

The cost function Y is:

$Y=4*\bar{CP}+5*\bar{PM}=4x+5\sqrt{(33-x)^2+9^2}$

To optimize this cost funtion we have to derive and equal to 0:

$\dfrac{dY}{dx}=0\\\\\\\dfrac{dY}{dx}=4+5(\dfrac{1}{2})((33-x)^2+9^2)^{-1/2} *(-2)(33-x)\\\\\\\dfrac{dY}{dx}=4+5\dfrac{x-33}{\sqrt{(33-x)^2+81}}=0\\\\\\\dfrac{x-33}{\sqrt{(33-x)^2+81}}=-\dfrac{4}{5}\\\\\\(x-33)=-\dfrac{4}{5}\sqrt{(33-x)^2+81}\\\\\\(x-33)^2=(-\dfrac{4}{5})^2[(x-33)^2+81]\\\\\\(x-33)^2=\dfrac{16}{25}(x-33)^2+\dfrac{1296}{25}\\\\\\\dfrac{25-16}{25} (x-33)^2=\dfrac{1296}{25}\\\\\\9(x-33)^2=1296\\\\\\x-33=\sqrt{\dfrac{1296}{9}}=\sqrt{144}=\pm12\\\\\\x=33\pm12\\\\\\x_1=33-12=21\\\\x_2=33+12=45$

The valid solution is x=21, as x can not phisically larger than 33.

The cost then becomes:

$Y=4*\bar{CP}+5*\bar{PM}=4x+5\sqrt{(33-x)^2+9^2}\\\\\\Y=4*21+5\sqrt{(33-21)^2+81}\\\\Y=81+5\sqrt{144+81}\\\\Y=81+5\sqrt{225}\\\\Y=81+5*15\\\\Y=81+75\\\\Y=156$

6 0

3 years ago

The probability that a student has a Visa card (event V) is .76. The probability that a student has a Master card (event M) is .

Rufina [12.5K]

Answer:

The Probability of both happening is <u>0.304</u>.

Step-by-step explanation:

P(A) × P(B)

= 0.76 × 0.4

= <u>0.304</u>

8 0

2 years ago

Two angles are supplementary. The larger angle is three times the smaller

melomori [17]

9514 1404 393

Answer:

45°, 135°

Step-by-step explanation:

The total of the two angles is 1+3 = 4 times the smaller angle. The total is 180°, so the smaller angle is

180°/4 = 45°

The larger angle is 3×45° = 135°

The two angles are 45° and 135°.

6 0

3 years ago

Let see if this work

allochka39001 [22]

Answer:

i really dont know what you are saying, but thanks for the points and have a nice day! always smile peeps!

3 0

3 years ago