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3 years ago

Write a kinda short song about 1 polygon with a familiar tune

Mathematics

1 answer:

STALIN [3.7K]3 years ago

3 0

A triangle is A polygon with 3 angles(x2) 3 sides

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How do I solve this equation? Please, if you will, explain.

Licemer1 [7]

Yes, but your answer will be a decimal, but make sure you check your work and one way you can check your work is by first combing like terms, and then solve it as it is an equation.

7 0

2 years ago

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Find the inverse of f(x)= 0.5x -1

Ghella [55]

Answer:

Y=2x+2

Step-by-step explanation:

Y=0.5x-1

To find inverse, switch and y

x=0.5y-1

0.5y=x+1

Y=2x+2

6 0

3 years ago

Read 2 more answers

Complete the table of values for this absolute value function. Then use the drawing tool(s) to graph the function. F(x)-2|x+1|-1

rusak2 [61]

Answer:

Please check the explanation!

Step-by-step explanation:

Given the equation

$f\left(x\right)=-2|x+1|-1$

As some of the absolute rules are:

$\left|a\right|=a,\:a\ge 0$

$\:|-a|=a,\:\quad \:a>0$

NOW, let us solve!

Let us substitute all the table values

Putting x = -4

$y=-2\left|-4+1\right|-1$ ∵ $\mathrm{Apply\:absolute\:rule}:\quad \left|a\right|=a,\:a\ge 0$

$y=-6-1$

$y=-7$

So, when x = -4, then y = -7

Putting x = -3

$y=-2|-3+1|-1\:$

$y=-4-1$

$y=-5$

when x = -3, then y = -5

Putting x = -2

$y=-2\left|-2+1\right|-1$

$y=-2-1$

$y=-3$

when x = -2, then y = -3

Putting x = -1

$y=-2\left|-1+1\right|-1$

$y=-0-1$

$y=-1$

when x = -1, then y = -1

Putting x = 0

$y=-2\left|0+1\right|-1$

$y=-2-1$

$y=-3$

when x = 0, then y = -3

Putting x = 1

$y=-2\left|1+1\right|-1$

$y=-4-1$

$y=-5$

when x = 1, then y = -5

The graph is also attached below.

6 0

2 years ago

there has to be at least one operating path. Once a component fails on a path, that path is no longer operating. The reliability

Eva8 [605]

Answer:

$R = P(R_1) P(R_2|R_1) P(R_3|R_2)*....*P(R_n |R_1,..., R_{n-1}$

For this case the reliability of the sytem would be given by:

$R= \prod_{i=1}^n R_i$

R1= 0.95, R2 =0.95, R3= 0.5, R4 = 0.79 , R5 = 0.6

And replacing we got:

$R = 0.95*0.95*0.5*0.79*0.6= 0.21389$

Step-by-step explanation:

We can assume that the system work in series

If we have in general n units the reliability of the system is the probability that unit 1 succeeds and unit 2 succeeds and all of the other units in the system succeed. fror n units must succeed for the system to succeed. The reliability of the system is then given by:

$R = P(R_1) P(R_2|R_1) P(R_3|R_2)*....*P(R_n |R_1,..., R_{n-1}$

For this case the reliability of the sytem would be given by:

$R= \prod_{i=1}^n R_i$

R1= 0.95, R2 =0.95, R3= 0.5, R4 = 0.79 , R5 = 0.6

And replacing we got:

$R = 0.95*0.95*0.5*0.79*0.6= 0.21389$

8 0

2 years ago

Simplify.

ivanzaharov [21]

5 - [ - (-2)] =
5 - [ 2 ] =
5 - 2 =
3 <==

3 0

2 years ago

Read 2 more answers