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3 years ago

Please help PLEASE Which equations are equal to this equation? 14(8x + 56) = 20

Mathematics

2 answers:

kvasek [131]3 years ago

7 0

Answer:

Here are a few equivalent equations:

112x + 784 = 20

112x = -764

x = -6.82

Step-by-step explanation:

14(8x + 56) = 20

Multiply

112x + 784 = 20

Subtract 784 from both sides of the equation

112x = -764

x = -6.82

Hope this was useful to you!

TEA [102]3 years ago

3 0

Answer:

x = - 191/28

Step-by-step explanation:

14 (8x + 56) = 20

112x + 784 = 20

112x = 20 - 784

112x = - 764

x = - 764/112

x = - 191/28

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ruslelena [56]

Answer:

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Step-by-step explanation:

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3 years ago

320% expressed as a mixed number in sinplest from is

UNO [17]

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3 years ago

Read 2 more answers

Let a1equals[Start 3 By 1 Matrix 1st Row 1st Column 1 2nd Row 1st Column 2 3rd Row 1st Column negative 1 EndMatrix ], a2equals[

Zolol [24]

Answer:

For h= 25, b in the plane spanned by a1 and a2

Step-by-step explanation:

$a1= \left[\begin{array}{c}1\\2\\-1\end{array}\right] \\a2 = \left[\begin{array}{c}-7\\-7\\2\end{array}\right] \\\\b = \left[\begin{array}{c}3\\-22\\h\end{array}\right]$

we have to find value of h for which b in the plane spanned by a1 and a2.

For this the linear systems given by the following augmented matrix must be consistent.

$\left[\begin{array}{cc|c}1&-7&3\\2&-7&-22\\-1&2&h\end{array}\right]$

Reduce the augmented matrix into row echelon form:

$R_{2} - 2R_{1} , R_{3} + R_{1}\\\\\left[\begin{array}{cc|c}1&-7&3\\0&7&-28\\-0&-5&h+3\end{array}\right]\\\\7R_{3}+5R_{2}\\\\\left[\begin{array}{cc|c}1&-7&3\\0&7&-28\\-0&0&7h-175\end{array}\right]$