For something to float the buoyant force ( force pushing up on the object to keep it floating) needs to equal the weight of the object
the answer would be: <span>weight of the ball</span>
Since both is equal to p(a), you can set them as equal to each other:
15 = 2a - 3
18 = 2a
9 = a
Answer:
5 shirts (read explanation)
Step-by-step explanation:
14x+29=100
14x=71
x=5.1
She can buy 5 shirts
Answer:
3u - 2v + w = 69i + 19j.
8u - 6v = 184i + 60j.
7v - 4w = -128i + 62j.
u - 5w = -9i + 37j.
Step-by-step explanation:
Note that there are multiple ways to denote a vector. For example, vector u can be written either in bold typeface "u" or with an arrow above it
. This explanation uses both representations.
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There are two components in each of the three vectors. For example, in vector u, the first component is 11 and the second is 12. When multiplying a vector with a constant, multiply each component by the constant. For example,
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So is the case when the constant is negative:
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When adding two vectors, add the corresponding components (this phrase comes from Wolfram Mathworld) of each vector. In other words, add the number on the same row to each other. For example, when adding 3u to (-2)v,
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Apply the two rules for the four vector operations.
<h3>1.</h3>

Rewrite this vector as a linear combination of two unit vectors. The first component 69 will be the coefficient in front of the first unit vector, i. The second component 19 will be the coefficient in front of the second unit vector, j.
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<h3>2.</h3>
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<h3>3.</h3>
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<h3>4.</h3>
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4 rows becsuse 261 × 4 = 1044. hop it helped