What is 490 miles traveled on Saturday and 225 miles on Sunday. About how many more miles did it travel on Saturday?

A jogger is running home. his distance from home, as a function of time, is modeled by y=-7+8.

Dovator [93]

Answer:

y=1

Step-by-step explanation:

4 0

3 years ago

Joey took a total of 12 pages of notes during 3 hours of class. after attending 4hours of class, how many pages of notes will jo

Delicious77 [7]

Answer:

If he kept taking notes at the same pace, he would have 16 pages of notes in his notebook.

Step-by-step explanation:

By dividing the number of pages of notes taken by the time spent taking them, you can find his rate of note-taking, which is 4 pages an hour. By adding another hour of notes, he should have 16 pages of notes. But if this question is asking for 4 more hours, the answer would be 28 pages.

4 0

3 years ago

Forensic specialists can estimate the height of a deceased person from the lengths of the person's bones. These lengths are subs

Lera25 [3.4K]

Answer:

$130.2845\leq h\leq 137.7245$

Step-by-step explanation:

Given an inequality that relates the height h, in centimeters, of an adult female and the length f, in centimeters, of her femur by the equation

$|h - (2.47f + 54.10)| \leq 3.72$

If an adult female measures her femur as 32.25 centimeters, we can determine the possible range of her height by plugging f = 32.25cm into the modelled equation as shown:

$|h - (2.47(32.25) + 54.10)| \leq 3.72\\|h - (79.9045 + 54.10)| \leq 3.72\\|h - (134.0045)| \leq 3.72\\$

If the modulus function is positive then:

$h - 134.0045 \leq 3.72\\h \leq 3.71+134.0045\\h\leq 137.7245$

If the modulus function is negative then:

$-(h - 134.0045) \leq 3.72\\-h+134.0045 \leq 3.72\\-h\leq 3.72-134.0045\\-h\leq -130.2845\\$

multiply through by -1

$-(-h)\geq -(-130.2845)\\h\geq 130.2845\\130.2845\leq h$

combining the resulting inequalities, the estimate of the possible range of heights will be $130.2845\leq h\leq 137.7245$

8 0

3 years ago

After a storm, 135 trees out of 180 were left standing. What is the percentage loss of the number of trees?

beks73 [17]

Answer:

Percentage loss of the number of trees is $25\%$ .

Step-by-step explanation:

Given: After a storm, $135$ trees out of $180$ were left standing.

To find: What is the percentage loss of the number of trees?

Solution:

We have,

Total number of trees $=180$

Number of trees left standing $=135$

Therefore, loss of trees $=180-135=45$

We now that $\text {Loss\%}=\frac{\text{Number of trees left}}{\text{Total number of trees}}\times 100 \%$

$\implies \text {Loss\%}=\frac{45}{180}\times 100 \%$

$\implies \text {Loss\%}=\frac{450}{18} \%$

$\implies \text {Loss\%}=25 \%$

Hence, the percentage loss of the number of trees is $25\%$ .

6 0

3 years ago

Put the following equation in standard form and determine the quadratic, linear, and constant coefficients. -3x2 - 8 = 5x - 7

marusya05 [52]

Answer:

-3x² -5x -1 = 0
-3 (quadratic)
-5 (linear)
-1 (constant)

Step-by-step explanation:

The equation will be in standard form when terms are listed in order of decreasing degree, and the right side of the equation is 0.

<h3>Standard form</h3>

We can subtract the right-side expression from both sides to get standard form.

-3x² -8 -(5x -7) = 5x -7 -(5x -7)

-3x² -8 -5x +7 = 0 . . . . . . . simplify a bit

-3x² -5x -1 = 0 . . . . . . . . . collect terms

The standard form equation can be written ...

-3x² -5x -1 = 0

<h3>Coefficients</h3>

The quadratic coefficient is the coefficient of the term with degree 2. The quadratic coefficient is -3.

The linear coefficient is the coefficient of the term with degree 1. The linear coefficient is -5.

The constant coefficient is the coefficient of the term with no variables. The constant is -1.

__

<em>Additional comment</em>

We can make the leading coefficient positive by multiplying the equation by -1. This gives ...

3x² +5x +1 = 0

with quadratic, linear, and constant coefficients 3, 5, 1.

This is a legitimate answer to this question. In the case of linear equations, the "standard form" has the constant on the right side of the equal sign, and the leading coefficient is required to be positive. A negative leading coefficient can sometimes lead to errors (when the sign is overlooked), so having a positive leading coefficient is often preferred.

8 0

2 years ago