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ser-zykov [4K]
3 years ago
6

How would you solve this:

Mathematics
1 answer:
kykrilka [37]3 years ago
7 0
3xy over 8 is the answer go to mathway
 and you can find your answer and it shows you how to do it


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Cody was 165cm tall on the first day of school this year, which was 10% taller than he was on the first day of school last year.
klemol [59]

Answer: 148.5


Step-by-step explanation:

well there is no real question here but cody is 165 which means you have to multiply that by 10% or 0.10 which gives you 16.5 and subtract that from the total

4 0
3 years ago
Solve the equation.<br> X-8=x-1<br> OX= 1<br> O X= 8<br> Ono solution<br> Oinfinitely many solutions
Veseljchak [2.6K]
I’m pretty sure it’s no solution
5 0
3 years ago
Read 2 more answers
8 in.<br> 8 in.<br> 8 in.<br> Find the area of the figure above.<br> [?] in2
RideAnS [48]

Answer:

96

Step-by-step explanation:

Total area = area of cube + area of triangle

A = 8² +  = 64 + 32 = 96 in

5 0
3 years ago
A rectangle with an area of 16 square units is drawn on a coordinate grid. The rectangle is
arsen [322]

Answer:

Just multiply x and y by the scale factor

Step-by-step explanation:

5 0
3 years ago
Find the angle between 4i−6j and −i 5j. (round to the nearest tenth of a degree if necessary. ) The angle between the vectors is
GarryVolchara [31]

If the vectors are 4i-6j and -i-5j then the angle between both the vectors is approximately 45°.

Given two vectors be  4i-6j and -i-5j.

We are required to find the angle between vectors  4i-6j and -i-5j.

A vector is basically an equation involving a linear combination of vctors with possibly unkown coefficients. Vector is basically a quantity that has both magnitude and direction but not possition.

Angle is basically measure of inclination of something with the surface.

The angles between two vectors can be find out by the following formula:

cos Θ=[dot product of both the vectors/(product of magnitude of both the vectors)

cos Θ=[4*(-1)+(-6)*(-5)]/\sqrt{4^{2} +(-6)^{2} } *\sqrt{(-1)^{2} +(-5)^{2} }

cos Θ=(-4+30)/\sqrt{52}\sqrt{26}

cos Θ=26/\sqrt{1352}

cos Θ=26/26.77

cos Θ=0.7070

Θ=cos^{-1}(0.707)

Θ=45.008

Approximately 45°.

Hence if the vectors are 4i-6j and -i-5j then the angle between both the vectors is approximately 45°.

Learn more about vectors at brainly.com/question/25705666

#SPJ4

3 0
2 years ago
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