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3 years ago

H(x) = x2 + 1 k(x) = x – 2 (h + k)(2

Mathematics

2 answers:

Mandarinka [93]3 years ago

6 0

(h + k)(2) = 5

(h - k)(3) = 9

evaluate 3h(2) + 2k(3) = 17

ratelena [41]3 years ago

6 0

Answer: 5

Step-by-step explanation:

Given h(x) = x²+1 and k(x) = x-2

h(x)+k(x) = (x²+1)+(x-2)

h(x)+k(x) = x²+x-1

To get (h+k)(2), we will substitute x=2 into the resulting function to give

(h+k)(2) = 2²+2-1

(h+k)(2) = 6-1

(h+k)(2) = 5

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Yo plz help I suck at Pythagoras theoreom >:(

dybincka [34]

Answer:

Step-by-step explanation:

you didn't put the problem you are stuck on here, but i am willing to help you out in understanding Pythagorean theorem!

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the formula for this is

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to solve for it, you plug in the two sides you have. the most simple is the two sides that are not the hypotenuse. the hypotenuse is the longest side, which is also not connected to another side by a right angle.

you should then plug those numbers into a and b. if you're not too strong with squaring a number, just use a calculator! its super easy to plug into!

lets make a scenario, you have two sides that are 3 and 3 and you are trying to find your hypotenuse!

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when you put 3 to the 2nd power in the calculator, it gives you 9!

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7 0

4 years ago

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Answer:

Step-by-step explanation:

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Andrews [41]

Answer:

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Step-by-step explanation:

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stellarik [79]

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