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Vadim26 [7]
3 years ago
14

Which of the following could be the ratio of the length of the longer leg of a 30-60-90 to the length of its hypotenuse? CHECK A

LL THAT APPLY.
A. √3 : 2
B. 3 : 2√3
C. 1 : √3
D. 3√3 : 6
E. √3 : √3
F. √2 : √3

-Apex Learning, Geometry
Mathematics
1 answer:
8_murik_8 [283]3 years ago
4 0

Answer:

A. √3 : 2

D. 3√3 : 6

Step-by-step explanation:

In a triangle described as 30°-60°-90° triangle, the base angles are 90° and 60°

The side with angles 90° and 60° is the shortest leg and can be represented by 1 unit

The hypotenuse side is assigned a value twice the shorter leg value, which is 2 units

From Pythagorean relationship; the square of the hypotenuse side subtract the square of the shorter leg gives the square of the longer side

This is to say if;

The given the shorter leg = 1 unit

The hypotenuse is twice the shorter leg= 2 units

The longer leg is square-root of the difference between the square of the hypotenuse and that of the shorter leg

=2^2-1^2\\\\=4-1=3\\\\\\b^2=3\\\\\\b=\sqrt{3}

where the longer leg is represented by side b in the Pythagorean theorem, the hypotenuse by c and the shorter leg by a to make;

a^2+b^2=c^2

<u>Hence the summary is</u>

a=shorter leg= 1 unit

b=longer leg = √3 units

c=hypotenuse=2 units

The ratio of longer leg to its hypotenuse is

=√3:2⇒ answer option A

This is the same as 3√3:6 ⇒answer option D because you can divide both sides of the ratio expression by 3 and get option A

=3\sqrt{3} :6\\\\\\\frac{3\sqrt{3} }{3} :\frac{6}{3} \\\\\\=\sqrt{3} :2

Answers are :option A and D

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0.8 of a cake

Step-by-step explanation:

all you do is divide 4 by 5

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You have a math test. you plan to study 5/6 hour tonight and 3/4 hour tomorrow.
alekssr [168]

5/6 of an hour is 50 Minutes

3/4 of an hour is 45 Minutes

6 0
3 years ago
PLEASE HELP AND SHOW WORK!!
Nastasia [14]

Answer:

Pipe 1 alone fills a tank in 10 min

Pipe 2 alone fills the tank in 20 min

If both are turned on together, how long will it take to fill the tank???

Pipe 1 fills at the RATE of 1/10th tank per min

Pipe 2 fills at the RATE of 1/20th tank per min

Pipe 1 + Pipe 2 fills at the rate of 1/10+1/20 or 3/20th tank per min

Let x= time to fill the tank

(3/20)(x)=1 Where 1 denotes a full tank (Multiply both sides by 20)

3x=20

x=6 2/3 min----------both working together

NOW YOUR PROBLEM

Let x= amount of time for smaller pipe to fill the tank

Then (x-5)=amount of time for larger pipe to fill the tank

NOW HERE'S WHERE THE RECIPROCAL COMES IN:

The smaller pipe fills the tank at the RATE of 1/x cu units per min

The larger tank fills the tank at the RATE of 1/(x-5) cu units per min

Together, they fill the tank at the rate of 1/x+(1/(x-5)) cu units per min

But now we are told that together the fill the tank in 11 1/9 minutes. so our equation to solve is:

(1/x+(1/(x-5))(11 1/9)=1 where 1 denotes a full tank. In fact, in each of the above reciprocals, the 1 denotes a full tank.

So, dividing both sides by 11 1/9, we get:

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I assume that you have no problems solviing this eq.

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Step-by-step explanation:

7 0
3 years ago
[4 - (3c - 1)][6 - ( 3c - 1)]
Anestetic [448]
Hi there!

You would have to simplify the terms inside [ ] this thing, then multiply.

So let's simplify them first.

4 - (3c - 1) 
use distributive property.....
4 - 3c + 1
-3c + 5

6 - (3c - 1)
use distributive property again...
6 - 3c + 1
-3c + 7

so now, multiply (-3c + 5)(-3c + 7).
(-3c + 5)(-3c + 7)
9c² - 21c - 15c + 35
9c² - 36c + 35

So your final answer is...
9c² - 36c + 35

Hope this helped! :)
3 0
3 years ago
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