All categories

3 years ago

I'd appreciate it if anyone could help out as soon as possible!

Mathematics

1 answer:

andriy [413]3 years ago

5 0

Answer:

(3x + 14) + (8x - 21) = 180º

Step-by-step explanation:

In order for the two lines to be parallel, the marked angles must be supplementary: their sum must be 180°.

You might be interested in

A house is worth 125,000 when it is 2 years old and 135,150 when it is 7 years old. According to this model, how much will the h

kicyunya [14]

Answer:111650

Step-by-step explanation:i think its right

4 0

3 years ago

ABC ~ ADE AC = 4, AE = 7, AD = 10, what is the length of AB? 1 3/7 2 1/2 5 5/7 17 1/2

Butoxors [25]

If the polygon or the figures are similar then it is known that the ratios of their corresponding sides and angles are proportional. In this item we can derive an equation that is,

AC/AE = AD/AB

Substituting the known values,

4/7 = 10/AB

AB from the equation is equal to 70/4 or equal to 17 ½.

3 0

3 years ago

Read 2 more answers

Which table of ordered pairs represents a proportional relationship?

natali 33 [55]

Answer:

Step-by-step explanation:

Every (x,y) pair is equal to each other, thus making them proportional :)

5 0

1 year ago

Since you guys said you couldn't see it last I reuploaded

prisoha [69]

It’s blank is the answer lol we can’t see it

7 0

3 years ago

Read 2 more answers

Use l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove

steposvetlana [31]

Answer:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}$

Step-by-step explanation:

The limit is:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}$

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$

hence, the limit of the function is -1/14

8 0

3 years ago