Question

If log x (8x-3)-logx4=2, the value of x is or .

Answer 1

X false -10 cg(centigrams)+8x-3

Answer 2

Answer:

$x = \dfrac{1}{2}$   or   $x = \dfrac{3}{2}$

Step-by-step explanation:

$log_x (8x - 3) - log_x {4} = 2$

$log_x \dfrac{8x - 3}{4} = 2$

$log_x (2x - \dfrac{3}{4}) = 2$

$x^2 = 2x - \dfrac{3}{4}}$

$4x^2 - 8x + 3 = 0$

$(2x - 1)(2x - 3) = 0$

$2x - 1 = 0$   or   $2x - 3 = 0$

$2x = 1$   or   $2x = 3$

$x = \dfrac{1}{2}$   or   $x = \dfrac{3}{2}$