His average is 86 so it is below 90. to get his average i just added all of his grades up to get 517 and then I divided 517 by 6 because thats how many grades he has and I got 86.
On the Grade row in the table it would go 83, 94, 79, 90, 96, 75 in order
The Above/Below 90 row would go -7, 4, 11, 7, -6, -3 in order
Lamont needs to get a 99 on his next test to have an average of exactly 90.
I HOPE THIS HELPED! PLEASE RATE ME AND MAKE MY ANSWER MOST BRAINLIEST!!
Answer: P(odd) = 0.499
Step-by-step explanation:
Given:
Total number of people = 20
Number of men = 12
Number of women = 8
Number of jury to be selected = 6
For the jury to have an odd number of women. it must have either of the three.
1. 1 woman , 5 men
2. 3 women, 3 men
3. 5 women, 1 man
The total possible ways of selecting the 6 people jury is;
N = 20C6 = 20!/6!(20-6)!
N = 38760
The possible ways of selecting;
Case 1 : 1 woman, 5 men
N1 = 8C1 × 12C5
N1 = 8 × 792 = 6336
Case 2 : 3 women , 3 men
N2 = 8C3 × 12C3
N2 = 12320
Case 3 : 5 women, 1 man
N3 = 8C5 × 12C1
N3 = 672
P(Odd) = (N1+N2+N3)/N
P(odd) = (6336+12320+672)/38760
P(odd) = 19328/38760
P(odd) = 0.499
For this case we have the following expression:
<span>

By properties of exponents we have:
Same basis, the exponents are added.
We have then:

Then, rewriting the exponent we have:

Therefore, an exponent to rewrite the expression is:
2
Answer:
an exponent to rewrite the expression is 2.</span>
Answer:
4 terms
Step-by-step explanation:
4is the number of variable terms that are in the expression 3x3y + 5x2 _ 4y + z + 9. The four variable terms in the expression are "xy", "x^2", "y" and "z"
Answer:
Example = ( 12, 1 )
Step-by-step explanation:
There are many possible solutions to this equation, and all you would have to do to determine the ordered pair, is satisfy the following criteria -

Take a look at a graph of the line y = 1 / 6x - 1. Any ordered pair that lies on this line is a solution to the equation. The " criteria " is that the ordered pair must lie on this line. Let me give you an example, ( 12, 1 ).
<u><em>Hope that helps!</em></u>