<span>f(5)= 2+5 = 7
</span><span>g(5)= 5^2+5 = 25 +5 = 30
</span><span>(f - g) (-5) = 7 - 30 = -23
answer is </span><span>D.-23</span>
The solution is -3, good luck on anymore questions.
Answer:
The other solution of the system is ![(x,y) = (\frac{4}{5} ,\frac{3}{5} )](https://tex.z-dn.net/?f=%28x%2Cy%29%20%3D%20%28%5Cfrac%7B4%7D%7B5%7D%20%2C%5Cfrac%7B3%7D%7B5%7D%20%29)
Step-by-step explanation:
Here, the given set of equations are: y = 2x -1 and ![x^{2} + y^{2} =1](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%2B%20y%5E%7B2%7D%20%20%3D1)
Now, to solve them put y = 2x -1 in the second equation, so we get
⇒ ![x^{2} + (2x-1)^{2} =1](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%2B%20%282x-1%29%5E%7B2%7D%20%20%3D1)
Also, by ALGEBRAIC IDENTITY : ![(a-b)^{2} = a^{2} + b^{2} -2ab](https://tex.z-dn.net/?f=%28a-b%29%5E%7B2%7D%20%20%3D%20a%5E%7B2%7D%20%2B%20%20b%5E%7B2%7D%20-2ab)
So, implying above , we get
⇒ ![x^{2} + 4x^{2} + 1 -4x =1 or, 5x^{2} -4x =0](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%2B%204x%5E%7B2%7D%20%20%2B%201%20-4x%20%20%3D1%20%20or%2C%20%205x%5E%7B2%7D%20%20-4x%20%20%3D0)
Now,
⇒x(5x-4) =0
So, either x =0, or x = 4/5
As (0, -1) is already a given solution:
So, when x = 4/5 ,put in equation (1)
y = 2(5/2) -1 = (3/5)
Hence, the other solution of the system is ![(x,y) = (\frac{4}{5} ,\frac{3}{5} )](https://tex.z-dn.net/?f=%28x%2Cy%29%20%3D%20%28%5Cfrac%7B4%7D%7B5%7D%20%2C%5Cfrac%7B3%7D%7B5%7D%20%29)
Answer:
curtiss can buy 7 pounds of pistachios
Step-by-step explanation:
5 cappuccinos x $5 = 25, 32 - 25=7