Answer:
The issue of the great compromise resolved representation.
Step-by-step explanation:
15,17,19
Suppose the three odd integers are #n#, #n+2# and #n+4#
Their sum is:
#n + (n+2) + (n+4) = 3n+6#
#13# more than twice the largest of the three is:
#2(n+4)+13 = 2n+21#
From what we are told these two are equal:
#3n+6 = 2n+21#
Subtract #2n+6# from both sides to get:
#n = 15#
So the three integers are:
#15, 17, 19#
Step-by-step explanation:
First term(a) = 1
Common difference(d)=2-1=1
No.of term(n)=50
Sn=n÷2(n+1)=50÷2(50+1)=1275
