Answer:
Take the first two expressions (you can actually take any two expressions): $\frac{a+b-c}{c}=\frac{a-b+c}{b}$.
$\frac{a+b}{c}=\frac{a+c}{b}$
$ab+b^2=ac+c^2$
$a(b-c)+b^2-c^2=0$
$(a+b+c)(b-c)=0$
$\Rightarrow a+b+c=0$ OR $b=c$
The first solution gives us $x=\frac{(-c)(-a)(-b)}{abc}=-1$.
The second solution gives us $a=b=c$, and $x=\frac{8a^3}{a^3}=8$, which is not negative, so this solution doesn't work.
Therefore, $x=-1\Rightarrow\boxed{A}$.
Step-by-step explanation:
Answer:
no
Step-by-step explanation:
iam sure they are not congruent
Answer:
They show as intersections with the x-axis
Step-by-step explanation:
For example, the quadratic y = x² - 1 has roots x = -1 and x = 1.
They show on the graph as intersections of the parabola with the x axis at x = -1 and x = 1.
Answer: The awnser is D
Step-by-step explanation: gabriel has 30 dollars and a 2 dollar off coupon. he can add the coupon to his total amount making 32 dollars. the money he spends on groceries is subtracted from that amount and is left with 32-2.5x-2y.
